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makvit [3.9K]
2 years ago
14

Please help me! It isn’t hard im just not sure how to do it .

Mathematics
1 answer:
pishuonlain [190]2 years ago
4 0

Answer:

a. Semester 1: 86.8, Semester 2: 87

b. Semester 1: 5.7, Semester 2: 6.3

c. Semester 1 because the standard deviation of the first semester was lower than of the second. This shows that his scores were closer to the mean and therefore he was more consistent.

Step-by-step explanation: Find the mean by taking the sum of the values for each semester and divide that sum by the number of values to find the average. Do this for both semesters. Now, find the absolute value of the difference between the mean and each value of the corresponding data set. Square each if those differences and sum them up. Now divide that sum by the number of data values and take the square root. This number is your standard deviation. You will use the standard deviations to make the comparison for part c. I hope this makes sense and helps!!!!

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A random sample of 64 bags of white cheddar popcorn weighed, on average, 5.23 ounces with a standard deviation of 0.24 ounce.
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Answer:

We conclude that cheddar popcorn weighed less than 5.5 ounces.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =5.5 ounces

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Sample standard deviation, σ = 0.24 ounce.

First, we design the null and the alternate hypothesis

H_{0}: \mu = 5.5\text{ ounces}\\H_A: \mu < 5.5\text{ ounces}

We use One-tailed z test to perform this hypothesis.

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z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }

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Since,  

z_{stat} < z_{critical}

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