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2 years ago

Please help me! It isn’t hard im just not sure how to do it .

Mathematics

1 answer:

pishuonlain [190]2 years ago

4 0

Answer:

a. Semester 1: 86.8, Semester 2: 87

b. Semester 1: 5.7, Semester 2: 6.3

c. Semester 1 because the standard deviation of the first semester was lower than of the second. This shows that his scores were closer to the mean and therefore he was more consistent.

Step-by-step explanation: Find the mean by taking the sum of the values for each semester and divide that sum by the number of values to find the average. Do this for both semesters. Now, find the absolute value of the difference between the mean and each value of the corresponding data set. Square each if those differences and sum them up. Now divide that sum by the number of data values and take the square root. This number is your standard deviation. You will use the standard deviations to make the comparison for part c. I hope this makes sense and helps!!!!

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2 years ago

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ludmilkaskok [199]

Answer:

a) 40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b) 34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

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In this question:

$\mu = 20, \sigma = 2$

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This is the pvalue of Z when X = 19.5. So

$Z = \frac{X - \mu}{\sigma}$

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40.13% probability that a laptop computer can be assembled at this plant in a period of time of less than 19.5 hours.

b)Between 20 hours and 22 hours?

This is the pvalue of Z when X = 22 subtracted by the pvalue of Z when X = 20. So

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X = 20

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$Z = \frac{20 - 20}{2}$

$Z = 0$

$Z = 0$ has a pvalue of 0.5

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34.13% probability that a laptop computer can be assembled at this plant in a period of time between 20 hours and 22 hours.

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