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goblinko [34]
3 years ago
10

find the area of the figure. all angles in the figure are right angles. please check this answer asap! thank you so much! ​

Mathematics
2 answers:
MissTica3 years ago
8 0

Answer:

57

Step-by-step explanation:

kifflom [539]3 years ago
8 0
<h2>Answer:</h2>

The area of the figure is: 57 mm²

<h2>Step-by-step explanation:</h2>

The area of figure is the sum of the area of rectangle (with dimensions 9 mm × 5 mm) and the second rectangle ( with dimensions 3 mm × 4 mm )

We know that the area of rectangle with dimensions a×b is ab square units.

Hence,

The area of rectangle with dimensions 9 mm×5 mm is: 45 mm²

and the area of rectangle with dimensions 3 mm×4 mm is: 12 mm²

Hence, the total area of figure is:

    45+12= 57 mm²

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alpha and beta are the zeros of the polynomial x^2 -(k +6)x +2(2k -1). Find the value of k if alpha + beta = 1/2 alpha beta(ITS
serious [3.7K]

Answer:

k=\frac{-11}{2}.

Step-by-step explanation:

We are given \alpha and \beta are zeros of the polynomial x^2-(k+6)x+2(2k-1).

We want to find the value of k if \alpha+\beta=\frac{1}{2}.

Lets use veita's formula.

By that formula we have the following equations:

\alpha+\beta=\frac{-(-(k+6))}{1}  (-b/a where the quadratic is ax^2+bx+c)

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Let's simplify those equations:

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Let's solve this for k:

Subtract 6 on both sides:

k=\frac{1}{2}-6

Find a common denominator:

k=\frac{1}{2}-\frac{12}{2}

Simplify:

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