Find a common denominator so, 3/6 plus 4/6 = 7/6
Answer:
y = [-½]x + [-5]
Step-by-step explanation:
Equation describing how x and y are related can be written in slope-intercept form, y = mx + b.
m = slope = ∆y/∆x
Using two pairs of values from the table, (-2, -4) and (0, -5),
Slope (m) = (-5 - (-4))/(0 - (-2)) = -1/2
m = -½
b = y-intercept = the value of y when x is 0 = -5
b = -5
✔️To write the equation, substitute m = -½ and b = -5 into y = mx + b
Thus:
y = [-½]x + [-5]
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
The expression 5x+3 would be three more than five times a number! More than in this case would be addition - so if you get the same problem with subtraction you just change more to less!
Basically what it's tell you is that if x stood for 2 in this case 5*2 = 10 since it's 3 MORE than 5 times a number (x is in place of a number), you're adding 3 to 10 and that gives you 13!
I hope I simplified it a little more and you understand!
Good luck, rockstar! c: I hope this helped!
Two consecutive odd integers whose product is 143 are 11 and 13.
