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denpristay [2]
3 years ago
5

If p is a polynomial show that lim x→ap(x)=p(a

Mathematics
1 answer:
Lostsunrise [7]3 years ago
3 0

Let p(x) be a polynomial, and suppose that a is any real number. Prove that

lim x→a p(x) = p(a) .

 

Solution. Notice that

 

2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .

 

So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x – 2.

 

Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| < 1, so −2 < x < 0. In particular |x| < 2. So

 

|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|

= 2|x|^3 + 5|x|^2 + |x| + 2

< 2(2)^3 + 5(2)^2 + (2) + 2

= 40

 

Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2 + x − 2| < ε/40 · 40 = ε.

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At 7:00 p.m., there are 1,000 home-team fans and 700 away-team fans at a football game. After 7:00 p.m, 15 home team fans arrive
OleMash [197]

Answer:

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=109:67

Step-by-step explanation:

Initially , total home team fans =1000

and away team fans = 700.

7:00 pm to 8:00 pm = 1 hour = 60 minutes

Given that

Every 10 minutes the number of arrival home team fans is 15.

Then in 1 minutes the number of arrival home team fans is \frac{15}{10}

and in 60 minutes the number of arrival home team fans is \frac{15 \times 60}{10}  

                                                                                                 =90

Therefore total home team fans = (90+1000)=1090

Given that

Every 10 minutes 5 fans leave of away team  leave.

then in  1 minutes \frac{5}{10}  fans leave of away team  leave.

and In 60 minutes \frac{5\times 60}{10} =30  fans leave of away team  leave.

Since 30 away team fans leave.

Total away team fans = (700-30)=670

Therefore the ratio of home-team fan to away team fan at 8:00 p.m is

=1090:670

=109:67

4 0
3 years ago
3 divide by what number equals 5
marysya [2.9K]
First write the equation
3/n = 5

Multiply both sides by n
3/n * n = 5 * n

Simplify
3 = 5 * n

Divide both sides by 5
3/5 = 5 * n/5

Simplify
3/5 = n

Divide
0.6 = n


So 3/0.6 = 5
4 0
4 years ago
Short sleeve t-shirts cost $10 and long sleeve t-shirts cost $15. If the t-shirt shop made $485 selling 38 total t-shirts, how m
BartSMP [9]

Answer:

The t-shirt shop sold 21 long sleeve shirts and 17 short sleeve shirts.

Step-by-step explanation:

To solve this problem, we should create a system of equations.  Let's let short sleeve t-shirts be represented by the variable s and long sleeve t-shirts be represented by the variable l.  

We know that the shop sold 38 total shirts, or in other words, the amount of long sleeve and short sleeve shirts combined is 38.  If we write this as an equation, we get: s + l = 38.

We can make another equation with the prices of the shirts.  If we take each type of shirt and multiply each price by the number sold and add them together, we should get the shop's total profits.  Represented as an equation, this is: 10s + 15l = 485.

Now that we have two equations, we should try to solve the system.  In this case, it is easiest to use substitution, so we are going to rewrite the first equation in terms of one variable.

s + l = 38

s = 38 - l

If we substitute this equivalent value for the variable s into the second equation, we get:

10s + 15l = 485

10(38 - l) + 15l = 485

Now we have an equation that only has one variable, so we can simplify both sides and then isolate the variable.

380 - 10l + 15l = 485

380 + 5l = 485

5l = 105

l = 21

Now, we can substitute this value for l back into the first equation to solve for the variable s.

s + l = 38

s + 21 = 38

s = 17

Therefore, the t-shirt shop sold 21 long sleeve shirts and 17 short sleeve shirts.

Hope this helps!

5 0
3 years ago
Based on the diagram, which expresses all possible
qaws [65]

The expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

<h3>Properties of a triangle</h3>

From the question, we are to determine the expression that expresses all possible lengths of segment AB

From one of the properties of a triangle,

The <u>third side</u> of any triangle is greater than the difference of the other <u>two sides</u>; and the <u>third side</u> of any triangle is lesser than the sum of the <u>two other sides</u>

Then, we can write that

AB < 27 + 54

and

AB > 54 - 27

Putting the two inequalities together, we get

54 - 27 < AB < 27 + 54

27 < AB < 81

Hence, the expression that expresses all possible lengths of segment AB is 27 < AB < 81. The correct option is the second option 27 < AB < 81

Learn more on the Properties of a triangle here: brainly.com/question/1851668

#SPJ1

3 0
2 years ago
How would you also do this??
Vesna [10]

4(5x + 7) = 128

First, I'd do distributive property and get:

20x + 28 = 128

Then, subtract 28 from each side.

20x = 100

Next, I'd divide 100 by 20 = 5

x = 5

4 *(5(5) + 7) = 128

5 * 5 = 25

4 * (25 + 7)

4 * 32 = 128

Therefore, the perimeter = 2l + 2w

l = 4

w = 5x + 7

BUT we know that x = 5

w = 5(5) + 7 = 32

2(4) + 2(32)

8 + 64 = 72

Therefore, the perimeter would be 72 inches.

5 0
3 years ago
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