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sveticcg [70]
3 years ago
9

Find two consecutive odd integers whose product is 143

Mathematics
1 answer:
Dennis_Churaev [7]3 years ago
4 0
Two consecutive odd integers whose product is 143 are 11 and 13.
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Flip a coin and toss a 1-6 number cube. Probability of: (heads and not a 3)
jeka94
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6 0
3 years ago
Which expression is equivalent to 3(6m) + m? A. 19m B. 21m C. 7m + 3 D. 18m + 6m²
Lelechka [254]

Answer:

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Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Eight people are entered in a race. If there are no ties, in how many ways can the first three places come out? a.336 b.368 c.67
Luden [163]
The first thing to do is to calculate how many ways you can choose 3 people from a set of eight.  In order to do this, we need to use the attached formula.
(The letter 'n' stands for the entire set and 'r' stands for the number of objects we wish to choose.)
So we wish to choose 3 people ('r') form a set of 8 ('n')
combinations = n! / r! * (n - r)!
combinations = 8 ! / (3! * 5!)
combinations = 8 * 7 * 6 * 5! / (3!) * (5!)
combinations = 8 * 7 * 6 / 3 * 2
combinations = 56

Now of those 56 combinations, the 3 people can finish in 6 different ways.
For example, persons A, B and C could finish
ABC or ACB or BAC or BCA or CAB or CBA

So to get the TOTAL combinations we multiply 56 * 6 which equals
336 so the answer is (a)


8 0
3 years ago
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