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3 years ago

6

In a list of numbers, the pattern increases by 0.001 as you move to the right. If the third number in the list is 0.046, what is

the first number in the list? Explain how you know.

1 answer:

pickupchik [31]3 years ago

3 0

Start with counting back from 0.046 three numbers

0.046, 0.045, 0.044

The answer for the first number that you started at is 0.044

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romanna [79]

I believe the answer is 8

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2 years ago

-3y+1/3=-5/6y-5/2 what does y equal

kotykmax [81]

Answer:

17/13

Step-by-step explanation:

$- 3y + \frac{1}{3} = - \frac{5}{6}y - \frac{5}{2} \\ - \frac{18}{6}y + \frac{2}{6} = - \frac{5}{6} y - \frac{15}{6} \\ \frac{2}{6} + \frac{15}{6} = - \frac{5}{6} y + \frac{18}{6} y \\ \frac{17}{6} = \frac{13}{6} y \\ \frac{6}{13} \times \frac{17}{6} = y \\ \frac{17}{13} = y$

8 0

3 years ago

If the factors of function f are (x - 6) and (x - 1), what are the zeros of function f?

lidiya [134]

X=6 and x=1

You can find your zeros by determining what you have to plug into the function in order for it to equal zero

If we plug in 6, for example we’d get (6-6)(x-1)

Simplified this is 0(x-1)

Anything times 0 is 0, so this is one of our zeros.

Same goes for x-1, we just need to plug in 1 for it to equal 0

Therefore there are zeros at x=1 and x=6 :))

7 0

3 years ago

B) The price of an electric fan is fixed 20% above its cost price. When it is sold allowing

kenny6666 [7]

Answer:

$\boxed{ \boxed{ \sf {Marked \: price \: = Rs \: 1500}}}$

$\boxed{ \bold{ \boxed{ \sf{Selling \: price = \: Rs \: 1230}}}}$

Step-by-step explanation:

Let Cost price ( C.P ) be x

<u>Finding </u><u>the </u><u>Marked </u><u>price </u><u>and </u><u>selling </u><u>price </u>

Marked price = $\sf{x + 20\% \: of \: x}$

⇒ $\sf{x + \frac{20}{100} \times x}$

⇒ $\sf{ \frac{x \times 100 + 20x}{100} }$

⇒ $\sf{ \frac{120x}{100} }$ ⇒ ( i )

Selling price = $\sf{marked \: price \: - 18\% \: of \: marked \: price}$

⇒ $\sf{ \frac{120x}{100} - \frac{18}{100} \times \frac{120x}{100} }$

⇒ $\sf{ \frac{120x}{100} - \frac{54x}{250} }$

⇒ $\sf{ \frac{120x \times 5 - 54x \times 2}{500} }$

⇒ $\sf{ \frac{600x - 108x}{500} }$

⇒ $\sf{ \frac{492x}{500} }$ ⇒ ( ii )

<u>Finding </u><u>the </u><u>value </u><u>of </u><u>x </u><u>(</u><u> </u><u>Cost </u><u>price </u><u>)</u>

$\sf{loss = cost \: price - selling \: price}$

⇒ $\sf{20 = x - \frac{492x}{500} }$

⇒ $\sf{20 = \frac{x \times 500 - 492x}{500} }$

⇒ $\sf{20 = \frac{8x}{500} }$

⇒ $\sf{8x = 10000}$

⇒ $\sf{x = \frac{10000}{8} }$

⇒ $\sf{x = \: Rs \: 1250}$

Value of x ( cost price ) = Rs 1250

<u>Now</u><u>,</u><u> </u><u>Replacing </u><u>the </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>i </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>marked </u><u>price</u>

$\sf{marked \: price = \frac{120x}{100} }$

⇒ $\sf{ \frac{120 \times 1250}{100} }$

⇒ $\sf{ \: Rs \: 1500}$

<u>Replacing </u><u>value </u><u>of </u><u>x </u><u>in </u><u>(</u><u> </u><u>ii </u><u>)</u><u> </u><u>in </u><u>order </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>selling </u><u>price</u>

$\sf{selling \: price = \frac{492 \: x}{500} }$

⇒ $\sf{ \frac{615000}{500} }$

⇒ $\sf{ \: Rs \: 1230}$

Thus , Marked price of the fan = Rs 1500

Selling price of the fan = Rs 1230

Hope I helped!

Best regards!!

6 0

3 years ago

melamori03 [73]

Use PEMDAS method to execute operations in the following order:

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

First equation:

12 + (38 - 18)2 = 12 + 20 × 2 = 52

Second equation:

(12)2 - 6(2 - 23) = 24 - 6(-21) = 24 + 126 = 150

Hope this helps.

5 0

3 years ago