You would start by saying his budget is $80 so you start with 80= he pays an initial fee of $59.50 every month plus $5 per gigabyte so you would set it up like
80=59.50+5x
X being how many gigabytes he uses then you solve 80-59.50 is 20.5 divided by 5 gives you 4.1 but you round down cause you don’t want to pass the limit so therefor the most gigabytes he can use is 4
9514 1404 393
Answer:
a9 = -8 +9(9 -1)
Step-by-step explanation:
The given sequence has a common difference of 1-(-8) = 10-1 = 9, and a first term of -8. The formula for the n-th term of such an arithmetic sequence is ...
an = a1 +d(n -1) . . . . . first term a1, common difference d
For the parameter of this sequence, a1=-8 and d=9, the n-th term is ...
an = -8 +9(n -1) . . . . formula for the n-th term
__
Then the formula for the 9th term is ...
a9 = -8 +9(9 -1)
X-5y=-21
x=-21+5y
-6(-21+5y)+4y=10
126+-30y+4y=10
126+-26y=10
-26y=-116
y=4.4615
x=1.3076
