Question

A bowl contains 3 red, 8 blue, and 7 black beads. Margaret randomly selects 3 beads one after the other without replacement. Find the probability of getting a red, blue, and black bead, in that order.

Answer 1

"There is a total of 18 beads. P(R) for first pick: 3/18 Now there are 17 beads left, of which 8 are blue. P(B) for second pick: 8/17 Now there are 16 beads left, of which 7 are black: P(K) for third pick: 7/16 Probability of all three events happening in that order would be P(RBK)=P(R)*P(B)*P(K)=?"

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