Question

The digits of both the two-digit numbers in the first calculation below have been reversed to give the two-digit numbers in the second calculation. The answers to the two calculations are the same. 62 × 13 = 806 62 × 13 = 806 26 × 31 = 806 26 × 31 = 806 For which one of the calculations below is the same thing true?

Answer 1

Answer and Step-by-step explanation:

The computation is shown below:

As we assume a and b are together and c and d are together

So, the equation would be

$= ab \times cd$

$= (10a + b) \times (10c + d)$

= 100ac + 10(ad + bc) + bd

Now another equation i s

$= ba \times cd$

$= (10b + a) \times (10d + c)$

= 100bd  + 10(ad + bc)  + ac

Now take both equations together

So,

100ac  + 10(ad + bc)  +  bd  = 100bd  + 10(ad + bc)  + ac

99ac  =  99bd

ac = bd

Now Like here  a = 2   b = 10  and    c  = 5   d = 1

So,

ac = bd = 10

So we can take an example like this

So, by considering the

$62 \times 13 = 806$

And,

$26 \times 31 = 806$

We can the same amount

So in the given question, the choices are not there so we can calculate by the above method