Answer:
If you meant
, then the answer is approximately 0.866.
If you meant
, then the answer is approximately -2.909 which looks like what you meant based on the choices.
Step-by-step explanation:
![9^x+4=11](https://tex.z-dn.net/?f=9%5Ex%2B4%3D11)
First step is to get the exponential part by itself. The part that has the variable exponent which is the
term.
To do this we need to subtract 4 on both sides:
![9^x=11-4](https://tex.z-dn.net/?f=9%5Ex%3D11-4)
Simplify:
![9^x=7](https://tex.z-dn.net/?f=9%5Ex%3D7)
The equivalent logarithmic form is:
![\log_9(7)=x](https://tex.z-dn.net/?f=%5Clog_9%287%29%3Dx)
I always say to myself the logarithm is the exponent that is how I know what to put opposite the side containing the log.
Anyways if you don't have options for computing
in your calculator you need to use the change of base formula.
![\frac{\log(7)}{\log(9)}=x](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clog%287%29%7D%7B%5Clog%289%29%7D%3Dx)
So ![x \approx 0.8856](https://tex.z-dn.net/?f=x%20%5Capprox%200.8856)
I don't see this as a choice so maybe you actually meant the following equation:
![9^{x+4}=11](https://tex.z-dn.net/?f=9%5E%7Bx%2B4%7D%3D11)
Let's see if this is the correct interpretation.
So the exponential part is already isolated.
So we just need to put in the equivalent logarithmic form:
![\log_9(11)=x+4](https://tex.z-dn.net/?f=%5Clog_9%2811%29%3Dx%2B4)
Now we subtract 4 on both sides:
![\log_9(11)-4=x](https://tex.z-dn.net/?f=%5Clog_9%2811%29-4%3Dx)
Again if you don't have the option for computing
in your calculator, you will have to use the change of base formula:
![\frac{\log(11)}{\log(9)}-4=x](https://tex.z-dn.net/?f=%5Cfrac%7B%5Clog%2811%29%7D%7B%5Clog%289%29%7D-4%3Dx)
![x \approx -2.909](https://tex.z-dn.net/?f=x%20%5Capprox%20-2.909)