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koban [17]
3 years ago
15

What is a pure monopoly?

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
5 0

Answer:

b

Not sure Hope It's help

Step-by-step explanation:

Not sure Hope It's Help

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Are ac and be congruent explain?
anzhelika [568]
AC is a line with length of 7 units, from -7 to 0 

BE is a line with length of 6 units, from 0 to 6

Two shapes are congruent if their length are the same, hence AC and BE is not congruent
4 0
3 years ago
HELP PLEASE I NEED HELP ON THIS PROBLEM "Three more than 8 times a number is -39.Find the number.
mr_godi [17]
8x + 3 = -39
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7 0
3 years ago
15 POINTS AND WILL MARK BRAINLIEST Help?? Pleasee
Rom4ik [11]

The <em>experimental probability</em> is calculated based on the results of the experiment; since the name Ted was chosen 26 times out of 123, the experimental probability is \boxed{\frac{26}{123}}.

Typically, the <em>theoretical probability </em>assumes that events are chosen randomly; since the name Ted is one of the 6 in the hat, the theoretical probability is \boxed{\frac{1}{6}}.

If we <em>increased</em> the number of names in the hat, we would expect both the experimental and theoretical probability to decrease, since there are now more names to choose from. Similarly, if we <em>decreased</em> the number of names in the hat, the experimental and theoretical probability would increase.

6 0
4 years ago
How many of the first 999 Fibonacci numbers are odd?
liq [111]
Every 3rd number is even with 2 odd numbers in between successive even numbers.

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6 0
3 years ago
Multiply the polynomials show steps
Karo-lina-s [1.5K]

Answer:

3a^{4} + 11a³ - 7a² + 18a - 18

Step-by-step explanation:

<u>When multiplying with two brackets, you need to multiply the three terms, (a²), (4a) and (-6) from the first bracket to all the terms in the second brackets, (3a²), (-a) and (3) individually. I have put each multiplied term in a bracket so it is easier.</u>

(a² + 4a - 6) × (3a² - a + 3) =

(a² × <em>3a²</em>) + {a² × <em>(-a)</em>} + (a² × <em>3</em>) + (4a × <em>3a²</em>) + {4a × <em>(-a)</em>} + (4a × <em>3</em>) + {(-6) × <em>a²</em>) + {(-6) × <em>(-a)</em>} + {(-6) × <em>3</em>}

<u>Now we can evaluate the terms in the brackets. </u>

(a² × 3a²) + {a² × (-a)} + (a² × 3) + (4a × 3a²) + {4a × (-a)} + (4a × 3) + {(-6) × a²) + {(-6) × (-a)} + {(-6) × 3} =

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18)

<u>We can open the brackets now. One plus and one minus makes a minus. </u>

3a^{4} + (-a³) + 3a² + 12a³ + (-4a²) + 12a + (-6a²) + 6a + (-18) =

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18

<u>Evaluate like terms.</u>

3a^{4} -a³ + 3a² + 12a³ -4a² + 12a -6a² + 6a -18 = 3a^{4} + 11a³ - 7a² + 18a - 18

5 0
3 years ago
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