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vivado [14]
4 years ago
11

F h(x) = −2x − 10, find h(−4).

Mathematics
2 answers:
Alex4 years ago
6 0
Just plug in the value of h(x):
h(-4)=-2(-4)-10
Now solve:
h(-4)=8-10
h(-4)=-2 :)
Nonamiya [84]4 years ago
5 0
U would replace ur -4 with the x’s so ur problem would look like <-2(-4)-10> and then solve that and u would get (2) for ur answer...
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Which expression is equivalent to (7x-5)-(3x-2)?
trapecia [35]
The answer would be A.
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3 years ago
Pauline, Patricia and Polly are pie bakers at their bakery, Perfect Pies. They bake four different pie flavors: cherry, blueberr
Shkiper50 [21]

Answer:

The answer is given below

Step-by-step explanation:

1) The persons are given by the matrix:

The number of different pie flavours is given by the matrix:

n=\left[\begin{array}{cccc}3&4&1&1\\6&6&4&6\\2&2&5&4\end{array}\right]

The cost of ingredients for each pie is given by the matrix:

I=\left[\begin{array}{ccc}3\\5\\2\\6\end{array}\right]

2)

\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{cccc}3&4&1&1\\6&6&4&6\\2&2&5&4\end{array}\right] \left[\begin{array}{ccc}3\\5\\2\\6\end{array}\right] \\\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{ccc}37\\92\\50\end{array}\right]

3) The cost of pie for Patricia = $92

The total cost of pie for all bakers = 37 + 92 + 50 = $179

The ratio of cost of Patricia pie to that of all three bakers = $92/$179 = 0.514

Patricia pie cost of ingredients is more than half of that of all three bakers

4)

The price of pie at Samuels sweet is represented by the matrix:

SA=\left[\begin{array}{ccc}8\\10\\7\\12\end{array}\right]

The income of each baker made by selling at samuels sweets is:

\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{cccc}3&4&1&1\\6&6&4&6\\2&2&5&4\end{array}\right] \left[\begin{array}{ccc}8\\10\\7\\12\end{array}\right] \\\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{ccc}83\\208\\119\end{array}\right]

The price of pie at Sugary Sarah is represented by the matrix:

SS=\left[\begin{array}{ccc}8\\9\\8\\13\end{array}\right]

The income of each baker made by selling at Sugary Sarah is:

\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{cccc}3&4&1&1\\6&6&4&6\\2&2&5&4\end{array}\right] \left[\begin{array}{ccc}8\\9\\8\\13\end{array}\right] \\\left[\begin{array}{ccc}Pauline\\Patricia\\Polly\end{array}\right] =\left[\begin{array}{ccc}81\\212\\126\end{array}\right]

5) Patricia yielded the greatest income. She made $208 + $212 = $420

6) Polly made $126 from selling at Sugary Sarah

7 0
3 years ago
Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of
zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

S = \theta r

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}

The arc length of the smaller gear is:

\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7

\displaystyle S_1=\frac{18.5\pi}{3}

The larger gear rotates the same arc length, so:

\displaystyle S_2=\frac{18.5\pi}{3}

\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}

Solving for θ2:

\displaystyle \theta_2=\frac{18.5\pi}{3r_2}

\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}

\theta_2=2.73\ radians

\displaystyle \theta_2=2.73*\frac{180}{\pi}=156

The larger gear will rotate through 156°

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Answer:

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Answer: 5 mm

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