Answer:
96
Step-by-step explanation:
We have to find number of 9 digit palindromes when all digits are even and each digit appearing not more than twice.
Digits used here
0,1,2,3,4,5,6,7,8,9
Total number of even digits=0,2,4,6,8=5
Now,
0 cannot be used for first place if number is 9-digit number.
Firs place can be filled by number of ways=4
Second place can be filled by number of ways=4
Third place can be filled by number of ways=3
Fourth place can be filled by number of ways=2
Fifth place can be filled by number of ways=1
Total number of ways=
Total number of ways=96
Hence, total number of 9-digits palindromes when all digits are even and appearing not more than twice=96
A) 35 B) 50. C) 85. D) 30
Do want me to explain it too?
Answer: 
***If you found my answer helpful, please give me the brainliest. :) ***
EQUATION: 5x = 2x - 9
Add 9 to both sides
NEW EQUATION: 5x + 9 = 2x
Subtact 5x from both sides:
NEW EQUATION: 9 = -3x
Divide -x on bith sides
NEW EQUATION: -3 = x, or x=-3
Answer:
(1, 8, 6) or (2, 12, 6) or (3, 24, 6)
Step-by-step explanation:
The last number must be 6:
1/2 = 6/12
The other two numbers cannot be 6, but can have several values:
1/2 = 1/8 +3/8 = 6/12
1/2 = 2/8 +3/12 = 6/12
1/2 = 3/8 +3/24 = 6/12
__
There are a variety of negative solutions as well. For example, ...
1/2 = -8/8 +3/2 = 6/12