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sineoko [7]
3 years ago
6

What does x and y equal if 3x-2 equal x-y equals 4

Mathematics
1 answer:
Alex17521 [72]3 years ago
3 0
<h3>x is 2 and y is -2</h3>

<em><u>Solution:</u></em>

Given that,

3x-2 equal x-y equals 4

Which means,

3x - 2 = x - y = 4

Therefore,

x - y = 4

Also,

3x - 2 = 4

Simplify above expression

3x - 2 = 4

3x = 4 + 2

3x = 6

Divide both sides by 3

x = 2

Substitute x = 2 in x - y = 4

2 - y = 4

y = 2 - 4

y = -2

Thus x is 2 and y is -2

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Answer:

\beta=45\degree\:\:or\:\:\beta=135\degree

Step-by-step explanation:

We want to solve \tan \beta \sec \beta=\sqrt{2}, where 0\le \beta \le360\degree.

We rewrite in terms of sine and cosine.

\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}

\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}

Use the Pythagorean identity: \cos^2\beta=1-\sin^2\beta.

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\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta

\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0

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By the quadratic formula, we have:

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\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }

\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }

\sin \beta=\frac{2}{2\cdot \sqrt{2} } or \sin \beta=\frac{-4}{2\cdot \sqrt{2} }

\sin \beta=\frac{1}{\sqrt{2} } or \sin \beta=-\frac{2}{\sqrt{2} }

\sin \beta=\frac{\sqrt{2}}{2} or \sin \beta=-\sqrt{2}

When \sin \beta=\frac{\sqrt{2}}{2} , \beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )

\implies \beta=45\degree\:\:or\:\:\beta=135\degree on the interval 0\le \beta \le360\degree.

When  \sin \beta=-\sqrt{2}, \beta is not defined because -1\le \sin \beta \le1

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Janine graphs these two lines and finds that they intersect.
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Step-by-step explanation:

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Step-by-step explanation:

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What is the value of x?<br><br> x + 13 = 59
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Answer:

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Step-by-step explanation:

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