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3 years ago

14

HELP PLEASE !!!!

2 answers:

kirill [66]3 years ago

8 0

Answer:

13 dimes

Step-by-step explanation:

If Maggie has only dimes and quarters in her purse. She has 27 coins with a total value of $4.05 in her purse. How many dimes does Maggie have in her purse then all you would have to do is divide 27 by .25

dimulka [17.4K]3 years ago

5 0

1. Let the shorter piece be x in. long
the longer piece will be x + 13 in. long
and the two pieces add up to be 47 in., so
x + ( x + 13 ) = 47
2x = 47 - 13
2x = 34
x = 17
the longer piece is x + 13 in. long,, or 17 + 13 = 30 in. long

2. number of dimes: x
number of quarters: y
x + y = 27....(1)
10x + 25y = 405...(2)
(1)*10: 10x + 10y = 270....(3)
(2) - (3):15y = 135
y = 9
plug y = 9 into (1), you will find that x = 18
so 18 dimes, 9 quarters

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Read 2 more answers

The edge length of a cube-shaped box is 2√5 inches long. Estimate the length of the edge to the nearest tenth of an inch. Then e

Shtirlitz [24]

Answer:

a) 4.5 inches

b) 2√5 is irrational

Step-by-step explanation:

It was given that the edge length of a cube-shaped box is 2√5 inches long.

To estimate the length of the edge to the nearest tenth of an inch, we change √5 to decimals to obtain:

$2 \sqrt{5} \approx2(2.26067977.....)$

$2 \sqrt{5} \approx4.47213955.....$

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4 years ago

Find the least common denominator for these two rational expressions. B/b^2 -64 -7b/b^2+7b-8

san4es73 [151]

Answer:

The least common denominator is (b-8)(b+8)(b-1)

Step-by-step explanation:

We are given expression as

$\frac{b}{b^2-64}-\frac{7b}{b^2+7b-8}$

Firstly, we will factor both denominators

$b^2-64=b^2-8^2=(b-8)(b+8)$

$b^2+7b-8=(b+8)(b-1)$

so, we can plug it back

$\frac{b}{(b-8)(b+8)}-\frac{7b}{(b+8)(b-1)}$

First term denominator is

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Second term denominator is

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So,

Least common denominator will be

(b-8)(b+8)(b-1)

So, we get

$LCD=(x-8)(x+8)(x-1)$

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3 years ago