We have to find the expected value for the PlayBall lottery.
The price of the ticket = $1
Prize amount = $250
If a player wins, he will be winning $249 as the price is not paid back along with the prize amount. He is spending $1, getting back $250, so the net amount he is getting back is $249.
Now we have to find the probability of winning and losing.
Number of letters from A to T = 20
Number of digits from 0 to 9 = 10
Probability of picking up the same letter that was picked on that day = 1/20
Probability of picking up the same number that was picked on that day = 1/10
Thus, the Probability of picking up the same letter and same number that was picked on that day =

Thus, the probability of winning = 1/200
The probability of losing =

The expected value E for the PlayBall lottery will be:
Thus, the option C gives the correct answer
Answer:
4 4/9
Step-by-step explanation:
First, you have to set it up: 5/9 times 8/1
We made it 8/1 since it has to be a fraction in the multipying ocess and the one does not change the value.
Next, Multiply.
5/9x8/1=40/9 as an inproper fraction
As a proper fraction, it is written as 4 4/9
Add both pair of shoes together. Then take that total and multiply by7% or.07
Answer: 1
Step-by-step explanation: it goes -7 -5 -3 -1 1