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kvv77 [185]
3 years ago
12

Find the formula for the nth term of the sequence: 0,7,18,33,52​

Mathematics
1 answer:
defon3 years ago
8 0

Answer:

t(n) = 2n² + n - 3

Step-by-step explanation:

<u>Given sequence: </u>

  • 0, 7, 18, 33, 52

Find the formula for nth term t(n)

<h3>Solution</h3>

<u>Sequence is neither arithmetic nor geometric, analyzing:</u>

  • 0, 7, 18, 33, 52

<u>First level difference</u>

  • 7, 11, 15, 19

<u>Second level difference</u>

  • 4, 4, 4

<u>As there are two levels, the formula should be in the form of:</u>

  • t(n) = an² + bn + c

<u>Trying the formula with the known terms:</u>

  • t(1) = 0 ⇒ a+b + c= 0
  • t(2) = 4a + 2b + c = 7 ⇒ 3a + b = 7
  • t(3) = 9a + 3b + c = 18 ⇒ 3(3a+b) + c = 18 ⇒ 21 + c = 18 ⇒ c = -3

<u>Going back to previous equations to find remaining coefficients:</u>

  • t(1) ⇒ a+ b = 3 ⇒ t(2) = 2a + (a+b) = 7 ⇒2a + 3 = 7 ⇒ a= 2 ⇒ b = 1

<u>So the formula becomes:</u>

t(n) = 2n² + n - 3

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