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diamong [38]
3 years ago
9

AABC has vertices at A(12, 8), B(4,8), and C(4, 14).

Mathematics
1 answer:
borishaifa [10]3 years ago
3 0

Answer:

<u>Triangle ABC and triangle MNO</u> are congruent. A <u>Rotation</u> is a single rigid transformation that maps the two congruent triangles.

Step-by-step explanation:

ΔABC has vertices at A(12, 8), B(4,8), and C(4, 14).

  • length of AB = √[(12-4)² + (8-8)²] = 8
  • length of AC = √[(12-4)² + (8-14)²] = 10
  • length of CB = √[(4-4)² + (8-14)²] = 6

ΔMNO has vertices at M(4, 16), N(4,8), and O(-2,8).

  • length of MN = √[(4-4)² + (16-8)²] = 8
  • length of MO = √[(4+2)² + (16-8)²] = 10
  • length of NO = √[(4+2)² + (8-8)²] = 6

Therefore:

  • AB ≅ MN
  • AC ≅ MO
  • CB ≅ NO

and ΔABC ≅ ΔMNO by SSS postulate.

In the picture attached, both triangles are shown. It can be seen that counterclockwise rotation of ΔABC around vertex B would map ΔABC into the ΔMNO.

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