Answer:
The equation for difference in altitude of the two helicopters is A = 650 - 100t
Step-by-step explanation:
Given;
The altitude of one helicopter is, A1 = 600 + 150t
The altitude of a second helicopter is, A2 = 1250 + 50t
Their difference in altitude, A at time t, is calculated as
A₂ - A₁ = A = (1250 + 50t) - (600 + 150t)
A₂ - A₁ = A = 1250 + 50t - 600 -150t
A₂ - A₁ = A = 1250 - 600 + 50t - 150t
A₂ - A₁ = A = 650 - 100t
Therefore, the equation for difference in altitude of the two helicopters is A = 650 - 100t
Answer:
3/5th
Step-by-step explanation:
look at the clock and you see half the clock so when you look at it you would know it is 3/5 because it has one arm and it is in the middle straight up so right on there is 3 and 5 where the dot is.
Answer:
b = 2.666.......
Step-by-step explanation:
------ -----
b = 2.666.....
Answer:
4 1/2 hours
Step-by-step explanation:
1 practice = 2 1/4 hours
2 practices = 4 1/2 hours
Answer:
x = 7.2
Step-by-step explanation:
Since LO is an angle bisector then the following ratios are equal
= 
, that is
= 
( cross- multiply )
10x = 72 ( divide both sides by 10 )
x = 7.2
