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Nata [24]
3 years ago
6

Molly use the expression 5(2b+3) to determine how many books (b) she needs to order for her store . If b=2 how may book will she

need to order?
Mathematics
1 answer:
AnnZ [28]3 years ago
7 0
5(2(2)+3)
5(4+3)
5(7)
b=35
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A professional cyclist is training for the Tour de France. What was his average speed in kilometers per hour if he rode the 194
Lisa [10]
Start with the distance equation D=RT, then plug in numbers

194=R x 4.2, so all we have to do is divide 194 by 4.2. 

Answer: 46.19 kph 
4 0
3 years ago
En una hoja de papel cuyo perímetro es de 96 centímetros, se quiere imprimir un volante de manera que el área impresa sea un rec
elixir [45]

Answer:

El perímetro de la región impresa es 72 cm y su área es 288 cm².  

Step-by-step explanation:

1. Tenemos el perímetro de la hoja de papel:

P₁ = 96 cm = 2l₁ + 2a₁  (1)  

Como sabemos el margen superior, inferior, izquierdo y derecho podemos encontrar la relación entre el largo y ancho del rectángulo interno (región impresa) con el largo (l) y ancho (a) del rectángulo externo (hoja de papel):      

l_{2} = l_{1} - (m_{s} + m_{i}) = l_{1} - (3 cm + 2 cm) = l_{1} - 5 cm  (2)            

a_{2} = a_{1} - (m_{d} + m_{iz}) = a_{1} - (2 cm + 5 cm) = a_{1} - 7 cm   (3)    

El perímetro del rectángulo interno es:

P_{2} = 2l_{2} + 2a_{2}    (4)

Introduciendo la ecuación (2) y (3) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2(l_{1} - 5 cm) + 2(a_{1} - 7 cm) = 2l_{1} + 2a_{1} - 10 cm - 14 cm = 96 cm - 24 cm = 72 cm  

Por lo tanto el perímetro del rectángulo interno (región impresa) es 72 cm.

 

2. Ahora para encontrar el área rectángulo interno debemos encontrar el largo y ancho del mismo, sabiendo que:

l_{2} = 2a_{2}     (5)

Introduciendo (5) en (4):

P_{2} = 2l_{2} + 2a_{2} = 2*2a_{2} + 2a_{2} = 6a_{2}

a_{2} = \frac{P_{2}}{6} = \frac{72 cm}{6} = 12 cm

l_{2} = 2a_{2} = 2*12 cm = 24 cm

Entonces el área es:

A_{2} = l_{2}*a_{2} = 12 cm*24 cm = 288 cm^{2}

Por lo tanto el área del rectágulo interno (región impresa) es 288 cm².      

Espero que te sea de utilidad!  

7 0
3 years ago
Find one terminating decimal and one repeating decimal between -1/2 and -1/3
Masteriza [31]
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3 years ago
Hahshxnxjennshsne did. D d d s s d d d
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7 0
3 years ago
On easter morning 20 eggs were hidden kyla found 1/2 of them kevin found 1/4 of them what fraction of eggs were left to find
kotykmax [81]
\frac{1}{2}*20= 10 
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To find the fraction, divide the number of eggs left over the number of total eggs.
Fraction= \frac{5}{20}= \frac{1}{4}

Hope this helps!
3 0
4 years ago
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