P1=(0,0)=(x1,y1)→x1=0, y1=0
P2=(3,-2)=(x2,y2)→x2=3, y2=-2
Slope: m=(y2-y1)/(x2-x1)
m=(-2-0)/(3-0)
m=(-2)/3
m=-2/3
Point-slope equation:
y-y1=m(x-x1)
y-0=(-2/3)(x-0)
y=-(2/3)x
Answer: The equation of the line is: y=-(2/3)x
1047.84ft² is not covered by the pool.
Find the area of the yard covered by pull using the area of a circle formula (the height is irrelevant in this case). If the diameter of the pool is 24 feet, its radius is 12 (half of the diameter)
A = 3.14r^2
A =3.14(144)
A = 452.16 ft²
Subtract the area of the pool from the area of the yard to get the area of the yard that is not covered by the pool. If the dimensions of the yard are 30ft by 50ft, you multiply them to get the area: 1500ft²
Total yard area: 1,500ft²
Area of yard without pool: 1,500ft² - 452.16ft² = 1047.84ft²
168
You add 4, 1, and 2 to get 7. You put 4/7=x/294. Then you use proportions to solve for x.
7x=1176
x=168
The bear beats its heart 50/6 times a minute during deep hibernation.
Thats 12 times a minute
45minutes x 12 times a minute
45x12 = 540
Answer: 540 times
