The minimum surface area that such a box can have is 380 square
<h3>How to determine the minimum surface area such a box can have?</h3>
Represent the base length with x and the bwith h.
So, the volume is
V = x^2h
This gives
x^2h = 500
Make h the subject
h = 500/x^2
The surface area is
S = 2(x^2 + 2xh)
Expand
S = 2x^2 + 4xh
Substitute h = 500/x^2
S = 2x^2 + 4x * 500/x^2
Evaluate
S = 2x^2 + 2000/x
Differentiate
S' = 4x - 2000/x^2
Set the equation to 0
4x - 2000/x^2 = 0
Multiply through by x^2
4x^3 - 2000 = 0
This gives
4x^3= 2000
Divide by 4
x^3 = 500
Take the cube root
x = 7.94
Substitute x = 7.94 in S = 2x^2 + 2000/x
S = 2 * 7.94^2 + 2000/7.94
Evaluate
S = 380
Hence, the minimum surface area that such a box can have is 380 square
Read more about surface area at
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I do not know for sure but im almost 100% sure that the answer is y=97 and x=1.08 i hope that is correct and that it helps you out.
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SOS HELP MAYDAY MADAY WER3E GOING DOWN BRUDDAS WE DONT KNOW DA WAE
Answer:
6
Step-by-step explanation:
It would be 6 because on a square, all the sides have to be the same length. The length of the square is equal to the base of the parallelogram.
Answer:
the dryer costs $425
Step-by-step explanation:
x = washer
y = dryer
x + y = 803
x = y - 47
using the second equation a substitute in the first equation we get
y - 47 + y = 803
2y = 850
y = $425
FYI
x = y - 47 = 425 - 47 = $378
