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marysya [2.9K]
3 years ago
8

What is the orgins of a line if the slope is -2

Mathematics
1 answer:
Reptile [31]3 years ago
8 0
Da answer is 1 lalala
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You are buying a new television and see it at the same price in several shops with various discounts.
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This is because of there different marketing statargies plus the reason behind this can be because they have high stock left and they want to clear that
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3 years ago
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A self-serve car wash charges $5.55 to use its facilities, plus an additional $0.67 for each minute the customer is at the self-
MA_775_DIABLO [31]

Answer:

10.91

Step-by-step explanation:

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6 0
2 years ago
Suppose z varies directly with x and inversely with the square of y. If z = 18 when I = 6 and y = 2, what is z when I 7 and y =
madam [21]

It is given that z varies directly with x and inversely with the square of y so it follows:

z=k\frac{x}{y^2}

It is also given that z=18 when x=6 and y=2 so it follows:

\begin{gathered} 18=k\frac{6}{2^2} \\ k=\frac{18\times4}{6} \\ k=12 \end{gathered}

So the equation of variation becomes:

z=12\frac{x}{y^2}

Therefore the value of z when x=7 and y=7 is given by:

\begin{gathered} z=\frac{12\times7}{7^2} \\ z=\frac{12}{7} \\ z\approx1.7143 \end{gathered}

Hence the value of z is 12/7 or 1.7143.

6 0
1 year ago
Please help in maths all answers.....2i/3-6i
pishuonlain [190]

Answer: 45 degrees I think


Step-by-step explanation:


5 0
3 years ago
Read 2 more answers
Rationalize the denominator.
Maslowich
If you're using the app, try seeing this answer through your browser:  brainly.com/question/3166412

——————————
 
     \mathsf{\dfrac{\sqrt{a}+2\sqrt{y}}{\sqrt{a}-2\sqrt{y}}}


Multiply and divide by the conjugate of the denominator, which is \mathsf{\sqrt{a}+2\sqrt{y}:}

     \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}\\\\\\ \mathsf{=\dfrac{\big(\sqrt{a}+2\sqrt{y}\big)^2}{\big(\sqrt{a}-2\sqrt{y}\big)\cdot \big(\sqrt{a}+2\sqrt{y}\big)}}

The numerator is a square of a sum, and the denominator is the product of a difference and a sum (product of two conjugates). Then, expand the common products:
 
     \mathsf{=\dfrac{\big(\sqrt{a}\big)^2+2\cdot \sqrt{a}\cdot 2\sqrt{y}+\big(2\sqrt{y}\big)^2}{\big(\sqrt{a}\big)^2-\big(2\sqrt{y}\big)^2}}\\\\\\ \mathsf{=\dfrac{a+4\cdot \sqrt{a}\cdot \sqrt{y}+2^2\cdot \big(\sqrt{y}\big)^2}{a-2^2\cdot \big(\sqrt{y}\big)^2}} 

     \mathsf{=\dfrac{a+4\sqrt{ay}+4y}{a-4y}}\quad\longleftarrow\quad\textsf{this is the answer.}


I hope this helps. =)

8 0
3 years ago
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