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Mars2501 [29]
3 years ago
7

Given the function y=-3(x-1)^2 -4, how do i find the range?

Mathematics
1 answer:
spin [16.1K]3 years ago
3 0
The vertex form:\ y=a(x-p)^2+q\ where\ (p;\ q)-coordinates\ of\ the\ vertex

The range of function y=ax^2+bx+c

if a > 0 then the range R = [q; ∞)
if a < 0 then the range R = (-∞; q]

We have: y=-3(x-1)^2-4\\\\a=-3 < 0\ and\ q=-4

therefore the range R=(-\infty;-4]
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4 years ago
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