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g100num [7]
3 years ago
11

Suppose that to make the golf team you need to score no more than 74 on average over 5 games. If you scored 77, 71, 77, and 67 i

n your first 4 games what is the highest score you can shoot in your 5th game and still make the team?
A. 76 B. 78 C. 79 D. 80
Mathematics
2 answers:
densk [106]3 years ago
7 0
(77 + 71 + 77 + 67 + x) / 5 = 74
(292 + x) / 5 = 74
292 + x = 74 * 5
292 + x = 370
x = 370 - 292
x = 78 <===
vivado [14]3 years ago
5 0
No more than 74 on average of 5 games means no more than 370 shots on total. If you add all of the numbers up you will get 292, so he can still shoot 370-292=78 in the last round, which is answer choice B.
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Step 1: Choose ONE of the following triangles and complete the table below:
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The question is incomplete below you will find the missing part.

Step 1 : Choose ONE of the following triangles complete the table below:

1. Obtuse Scalene Triangle Translation to prove SSS Congruence

or

2. Isosceles Right Triangle Reflection to prove ASA Congruence

or

3. Equilateral Equiangular Triangle Rotation to prove SAS Congruence

Original Coordinate Point

Transformation Rule

Image Coordinate Points

A (1, 4)      (x,y) -> (x+ ,y -)      A’ ( , )

B ( 7,4)     (x,y) -> (x+ ,y - )     B’ ( , )

C (8,9)      (x,y) -> (x+ ,y -)     C’ ( , )

The appropriate table is also shown below.

The triangles ABC and A'B'C' are congruent by SSS through Obtuse Scalene Triangle Translation  because the corresponding sides are congruent

Two triangles are congruent if their size and shape are the same.

Now we have to transform the triangle,

The coordinates of the triangle ΔABC are given as:

A = (1, 4)

B = (7,4)

C = (8,9)

so the lengths of the sides of the triangle are given by

AB= √(7-1)²+(4-4)²= √6²= 6

BC= √(8-7)²+(9-4)²= √1²+5²= √1+25= √26

CA= √(8-1)²+(9-4)²= √7²+5²= √49+25= √74

In order to prove the SSS congruence, we have to transform the triangles under the following translation rule:

(x,y) -> (x -3, y +6)

in the above translation,

The triangle will be translated 3 units left

And then translated 6 units up.

So, we have the new coordination of the points of the translated triangle ΔA'B'C'

A' = (1-3, 4+6)

A' = (-2, 10)

B' = (7-3, 4+6)

B' = (4, 10)

C' = (8-3, 9+6)

C' = (5, 15)

Now

so the lengths of the sides of the triangle are given by

A'B'= √(4-(-2))²+(10-10)²= √6²= 6

B'C'= √(5-4)²+(15-10)²= √1²+5²= √1+25= √26

C'A'= √(-2-5)²+(10-15)²= √(-7)²+(-5)²= √49+25= √74

By comparing two triangles ΔABC and ΔA'B'C'

AB ≅ A'B'

BC ≅ B'C'

CA ≅ C'A'

Hence ΔABC ≅ A'B'C' (By S-S-S rule)

By the above transformation, the triangles ABC and A'B'C' are congruent by SSS because the corresponding sides are congruent as all the points are gone through the same transformation.

Learn more about the transformation

here: brainly.com/question/4289712

#SPJ10

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There are about fourty-one thousand Asian elephants and about four-hundred seventy thousand African elephants left in the world
ivolga24 [154]
41000+470000=511000 elephants
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2 years ago
a carnival game consists of 3 dart throws at a target. The probability of scoring a hit on any one throw is 30%. Using the binom
Ghella [55]

Answer:  Probability of scoring 2 hits = 0.63.

Step-by-step explanation:

Since we have given that

Number of dart throws at a target = 3

Probability of scoring a hit on any one throw = 30%

We will use "Binomial Distribution" i.e.

P=^nC_rp^r(1-p)^{n-r}

where,

n denotes number of dart throws at a target,

r denotes number of required throws

p denotes probability of success

(1-p) denotes probability of failure

So, Probability of success is given by

\frac{30}{100}=\frac{3}{10}

Probability of failure is given by

1-\frac{30}{100}=\frac{70}{100}=\frac{7}{10}

We will use "Binomial Distribution" i.e.

P(X=2)=^3C_2(\frac{3}{10})^2\times (\frac{7}{10})\\\\P(X=2)=\frac{9}{100}\times \frac{7}{100}\\\\P(X=2)=\frac{63}{100}\\\\P(X=2)=0.63

Hence, Probability of scoring 2 hits = 0.63.

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Answer:

Rectangular what?

Step-by-step explanation:

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Answer:

The answer is c.

Step-by-step explanation:

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6 0
2 years ago
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