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Molodets [167]
3 years ago
7

Erin and dan went shopping at their local store. Erin bought shirts that cost $12 each and spent $18 on accessories. Dan bought

the same number of shirts as Erin for $16 each and spent $10 on accessories
Mathematics
1 answer:
andrezito [222]3 years ago
7 0

Answer:

2

Step-by-step explanation:

I  think below is your full question:

<em>Erin and Dan went shopping at their local store. Erin bought shirts that cost $12 each and spent $18 on accessories. Dan bought the same number of shirts as Erin for $16 each and spent $10 on accessories. </em>

<em>If Erin and Dan were billed the same amount by the store, how many shirts did each of them buy?</em>

Here is my answer

Let  x is number of shirts

Person             COST              

ERIN                12x+18

DAN                 16x+10

Equally Billed    12x+18=16x+10 <=> x = 2

so each of them buy 2 shirts

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Mr.Swanson bought a package of 10 disposable razors for $6.30. He found that each razor lasted for 1 week. What was the cost per
Blababa [14]

Answer:

9 cents per day

Step-by-step explanation:

1 week = 7 days

Each razor lasts 1 week = 7 days

10 razors last 10 weeks = 10 * 7 days = 70 days

cost per day = (total cost)/(number of days)

cost per day = $6.30/(70 days) = $0.09/day

4 0
2 years ago
A survey collected data on annual credit card charges in seven different categories of expenditures: transportation, groceries,
Andru [333]

Answer:

A. Null and alternative hypothesis:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

B. Yes. At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

P-value = 0.00002

C. As the difference is calculated as (population 1 − population 2), being population 1: groceries and population 2: dinning out, and knowing there is evidence that the true mean difference is positive, we can say that the groceries annual credit card charge is higher than dinning out annual credit card charge.

The point estimate is the sample mean difference d=$840.

The 95% confidence interval for the mean difference between the population means is (490, 1190).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

Then, the null and alternative hypothesis are:

H_0: \mu_d=0\\\\H_a:\mu_d\neq 0

The significance level is 0.05.

The sample has a size n=42.

The sample mean is M=840.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1123.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{1123}{\sqrt{42}}=173.2827

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{840-0}{173.2827}=\dfrac{840}{173.2827}=4.848

The degrees of freedom for this sample size are:

df=n-1=42-1=41

This test is a two-tailed test, with 41 degrees of freedom and t=4.848, so the P-value for this test is calculated as (using a t-table):

\text{P-value}=2\cdot P(t>4.848)=0.00002

As the P-value (0.00002) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

At a significance level of 0.05, there is enough evidence to support the claim that there is signficant difference between the population mean credit card charges for groceries and the population mean credit card charges for dining out.

We have to calculate a 95% confidence interval for the mean difference.

The t-value for a 95% confidence interval and 41 degrees of freedom is t=2.02.

The margin of error (MOE) can be calculated as:

MOE=t\cdot s_M=2.02 \cdot 173.283=350

Then, the lower and upper bounds of the confidence interval are:

LL=M-t \cdot s_M = 840-350=490\\\\UL=M+t \cdot s_M = 840+350=1190

The 95% confidence interval for the mean difference is (490, 1190).

7 0
2 years ago
A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati
Marina CMI [18]

Answer:

Minimum average cost = 743.75

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Step-by-step explanation:

Given the cost equation

C = 0.04x² − 5x + 900

To Obtian the minimum average cost ;

Find dc/dx = 0

Diffentiate cost, c it ith respect to x

dc/dx = 2(0.04x) - 5

dc/dx = 0.08x - 5 = 0

0.08x = 5

x = 5 / 0.08

x = 62.5

Substitute the value of x into C to obtain the minimum average cost

C = 0.04(62.5)² - 5(62.5) + 900

C = 743.75

6 0
2 years ago
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Aleksandr-060686 [28]

Answer:

\huge\boxed{\sf (f-g)(x) = 3x\² + 4x - 14}

Step-by-step explanation:

<h3><u>Given functions:</u></h3>
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  • g(x) = x² - 4x - 8
<h3><u>Solution:</u></h3>

Subtract both functions

(f-g)(x) = 4x² - 6 - (x² - 4x - 8)

(f-g)(x) = 4x² - 6 - x² + 4x - 8

Combine like terms

(f-g)(x) = 4x² - x² + 4x - 6 - 8

(f-g)(x) = 3x² + 4x - 14

\rule[225]{225}{2}

3 0
2 years ago
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Iteru [2.4K]
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