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3 years ago

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On the football team, two out of every seven players are seniors. If the team has 84 players, how many of the players are not se

niors?

2 answers:

just olya [345]3 years ago

5 0

Answer: 60

Step-by-step explanation:

Given : The fraction of football players are senior = $\dfrac{2}{7}$

If the team has 84 players, then by using the MULTIPLICATION OPERATION, we have

The number of players are senior = $\dfrac{2}{7}\times84=24$

Then by using Subtraction operation , the number of players are not seniors =84-24=60

Dvinal [7]3 years ago

4 0

To find the answer, you must then divide 84 by 7, which is 12, and then realistically multiply the numerator of the first ration. Being 24 out of 84 football players are seniors, you just subtract 24 from 84, and you get 60 players.

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2 years ago

Find intercepts of: 3x-3y+9=0 <br> X-intercept as a ordered pair<br> Y-intercept as a ordered pairr

ahrayia [7]

3x - 3y + 9 = 0

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.

To solve for the y-intercept, set x = 0:

3(0) - 3y + 9 = 0
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Subtract 9 from both sides:
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Divide both sides by -3 to solve for y:

-3y/-3 = -9/-3
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Therefore, the y-intercept is (0, 3).

The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.

To solve for the x-intercept, set y = 0:

3x - 3(0)+ 9 = 0
3x -0 + 9 = 0

Subtract 9 from both sides:
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Divide both sides by 3 to solve for x:

3x/3 = -9/3
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Therefore, the x-intercept is (-3,0).

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2 years ago

Question 1,2, and 3 how do i factor those? Can you show the work and explain how?

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1: $3n^{2}+9n+6$

notice that each part is divisible by 3

$3n^{2}$ ÷ 3 = $n^{2}$

9n ÷ 3 = 3n

6 ÷ 3 = 2

so it becomes $3(n^{2} +3n+2)$

3n can be rewritten as 2n+n

-you want to rewrite it into two numbers that multiply to the number that's alone (in this case 2)

which would get you

$3(n^{2} +2n+n+2)$

Now that it's rewritten, you can factor out n + 2 from the equation.

<u><em>the answer is </em></u>

3(n+2)(n+1)

And you can check that by multiplying (n+2)(n+1) which is $n^{2} +2n+n+2$ and then each of those by 3, which is $3n^{2} +6n+3n+6$ or $3n^{2}+9n+6$ , our origional equation

2: $28+x^{2} -11x$

So I rewrote this as $x^{2} -11x+28$ (it's the same thing, just reordered using the commutative property)

now -11x can be rewritten as -4x-7x

(remember, the two numbers should multiply to equal 28, which is our constant.)

$x^{2} -4x-7x+28$

now we can factor out x from the first expression and -7 from the second

$x(x-4)-7(x-4)$

and lastly you factor out x-4,

<u><em>which would give you</em></u>

(x-4)(x-7)

Make sure to check your work and make sure it multiplies to $x^{2} -11x+28$

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So if you rewrite 9 as $3^{2}$ and 4 as $2^{2}$ , the equation becomes

$3^{2} x^{2} -12x+2^{2}$

now that $3^{2} x^{2}$ is ugly so it can be turned into $(3x)^{2}$

and -12x can be rewritten as $-2*3x*2$

so our equation now looks like $(3x)^2-2*3x*2+2^{2}$

There's a rule that says $a^{2} -2ab+b^{2} = (a-b)^{2}$

In our case, a=3x and b=2

<u><em>so the final answer is</em></u>

$(3x-2)^2$

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2 years ago

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eimsori [14]

The answer is x = -10

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2 years ago