Please help thanks!!

Please solve for the inverse variation equation

mojhsa [17]

Answer:

f(x) = $\frac{1}{x-2} + 1$

Step-by-step explanation:

First we identify the Vertical Asymptote. Which is at x = 2

The function has a VA only at the point where the denominator gives 0, so because we know x = 2 is the VA, the denominator will be x - 2.

Then we identify the Horizontal Asymptote, which is the behavior of the function for very large 'x', or the horizontal line of the graph on the y - axis. Which is at y = 1. So our function will go to 1, as x grows incredibly large.

But since our denominator is x - 2, the top remains 1, but we should add a 1 to the function so it really has a HA at y = 1.

f(x) = $\frac{1}{x-2} + 1$

8 0

4 years ago

Helppppppppppppppppppppp failingggggggggggggggg quizzzzzzzzzzzzzzzzzzzzzzzzzzzz

vladimir1956 [14]

Answer: 1.If two quadrilaterals are congruent, then there must be 4 pairs of corresponding sides. [C) is true]

2. Statement ∆KPT ≅ ∆KRT. [D) is true.]

3. If CDEF ≅ MNPQ, then ∠P ≅ ∠E [C) is true.]

4. If ∆LMC ≅ ∆BJK, then ∆MCL ≅ ∆JKB. [B) is true.]

5. If ABCDE ≅ LMNPQ, then there are 10 pairs of corresponding parts .

6. If ∠C ≅ ∠M, ∠E ≅ ∠Q, ED, ≅ QN,CD ≅MN and EC≅QM , then ∆CED ≅∆MQN [A) is true]

7. ∠B and ∠E will be a pair of corresponding parts if ∆ABC ≅ ∆DEF. [B) is true.]

8. B) is true.∆QPR ≅ ∆SPR

. [B) is true]

9. If two angles of one triangle are congruent to two angles of another triangle, then the third angles are congruent. [C) is true.]

10. If CDEF ≅ MNPQ, then ∠N ≅ ∠D. [C) is true.]

4 0

4 years ago

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Complete the equation of this line in slope-intercept form y= _x-1

Andre45 [30]

Answer:

it will be 3 hope that helps

4 0

3 years ago

Put the differential equation 9ty+ety′=yt2+81 into the form y′+p(t)y=g(t) and find p(t) and g(t). p(t)= help (formulas) g(t)= he

alexgriva [62]

Answer:

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous

Step-by-step explanation:

Given that,

The differential equation is -

$9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$

$e^{t}y' + (9t - \frac{1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t(t^{2} + 81 ) - 1}{t^{2} + 81 } )y = 0\\e^{t}y' + (\frac{9t^{3} + 729t - 1}{t^{2} + 81 } )y = 0\\y' + [\frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) } ]y = 0$

By comparing with y′+p(t)y=g(t), we get

$p(t) = \frac{9t^{3} + 729t - 1}{e^{t}(t^{2} + 81) }$

g(t) = 0

And

The differential equation $9ty + e^{t}y' = \frac{y}{t^{2} + 81 }$ is linear and homogeneous.

6 0

3 years ago

Three-fourths of a number increased by one-half is equal to fourteen. Find the number.

ivanzaharov [21]

Three-fourths of a number increased by one-half

= 3/4 x + 1/2

So three-fourths of a number increased by one-half is equal to fourteen:

3/4 x + 1/2 = 14

Multiply both sides by 4

3x + 2 = 56

Subtract 2 from both sides

3x = 54

Divide both sides by 3

x = 18

Answer: The number is 18

8 0

4 years ago

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