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3 years ago

Y=+4=3/4 (x-1) Find a point on the line and the lines slope

Mathematics

1 answer:

snow_tiger [21]3 years ago

3 0

Answer:

slope = -3/4

Step-by-step explanation:

Slope:

− 3/4

y-intercept:

13 /4

Any line can be graphed using two points. Select two values, and plug them into the equation to find the corresponding values.

x | y

0 | 13 /4

1 | 5/ 2

Hope this helps @(^_^)@

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A rocking horse has a weight limit of 60pounds. What percentage of the weight limit is 33 pounds? What percentage of the weight

bixtya [17]

Answer:

The percentage is 55% when weight limit is 33 pounds.

The percentage is 190% when weight limit is 114 pounds.

The 95% of the limit weighs 57 pounds.

Step-by-step explanation:

Given:

Weight limit of rocking horse = 60 pounds.

We need to find:

a) What percentage of the weight limit is 33 pounds.

b)What percentage of the weight limit is 114 pounds.

c) What weight is 95% of the limit.

Now Solving for a we get;

Weight limit = 33 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{33}{60}\times100 = 55\%$

Hence The percentage is 55% when weight limit is 33 pounds.

Now Solving for b we get;

Weight limit = 114 pounds

Now percentage of the weight limit can be calculated by dividing given weight limit with total weight limit and then multiplying by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{114}{60}\times100 = 190\%$

Hence The percentage is 190% when weight limit is 114 pounds.

Now Solving for c we get;

Percentage Weight = 95%

Now Amount of weight limit can be calculated by multiplying Percentage weight limit with total weight limit and then Dividing by 100 we get;

framing in equation form we get;

percentage of the weight limit = $\frac{95}{100}\times60 = 57 \pounds$

Hence The 95% of the limit weighs 57 pounds.

4 0

3 years ago

CE and FI are parallel, give reasons to prove that DGH is isosceles

Tresset [83]

Answer:

DGH has a different number than Ce and FI

4 0

3 years ago

The distances of a port from 20 differ- ent locations form an AP. If the farthest distance is 300 km, and the nearest distance i

Mkey [24]

Answer:

Required difference = 270/19 km

Step-by-step explanation:

If we consider the AP of distances to be

a, a + r, a + 2r, ..., a + 19r,

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

Given that,

a + 19r = 300 .....(1)

a = 30 ..... (2)

Using (2), from (1), we get

30 + 19r = 300

or, 19r = 300 - 30

or, 19r = 270

or, r = 270/19

Therefore the distance between any two successive location is 270/19 km.

5 0

2 years ago

0.4 times 0.59 sgaehags

ra1l [238]

Answer:

0.236

Step-by-step explanation:

Multiply 0.4 by 0.59

hopes this helps have a good day :) <3

brainlest???

5 0

2 years ago

A = 1/2 bh (solve for b)

Vikentia [17]

Answer:

Step-by-step explanation:

if A=1/2 bh

to solve for b

2A=bh

b=2A/h

4 0

2 years ago