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insens350 [35]
2 years ago
10

10. Choose a word from below to complete the sentence. A salary is called a(n) for the employer

Mathematics
2 answers:
Yuri [45]2 years ago
8 0

Answer:

Expanse

Step-by-step explanation:

BigorU [14]2 years ago
4 0
Expense is the right answer
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are given the sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3) A:name the communities A and B B:desc
4vir4ik [10]

Answer:

A n B = {6}

Step-by-step explanation:

Given he sets A = (even numbers less than 10) and B = (multiples of 3 greater than 3)

A = {2, 4, 6, 8}

B = {3, 6, 9, 12, 15...}

A n B includes the numbers are are common to both sets i.e number that we can find in both A and B.

From the set given, we can see that the only number that exists in both set is 6, hence;

A n B = {6}

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2 years ago
Total of y and five divided by x
Ede4ka [16]

Answer:

5y/x

Step-by-step explanation:

this is all i can write as an equation boo

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3 years ago
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For f(x)=4sin(x2) between x=0 and x=3, find the coordinates of all intercepts, critical points, and inflection points to two dec
telo118 [61]

Answer:

Intercepts:

x = 0, y = 0

x = 1.77, y = 0

x = 2.51, y = 0

Critical points:

x = 1.25, y = 4

x = 2.17 , y = -4

x = 2.8, y = 4

Inflection points:

x = 0.81, y = 2.44

x = 1.81, y = -0.54

x = 2.52, y = 0.27

Step-by-step explanation:

We can find the intercept by setting f(x) = 0

4sin(x^2) = 0

sin(x^2) = 0

x^2 = n\pi where n = 0, 1, 2,3, 4, 5,...

x = \sqrt(n\pi)

Since we are restricting x between 0 and 3 we can stop at n = 2

So the function f(x) intercepts at y = 0 and x:

x = 0

x = 1.77

x = 2.51

The critical points occur at the first derivative = 0

f^{'}(x) = 4cos(x^2)2x = 8xcos(x^2) = 0

xcos(x^2) = 0

x = 0 or

cos(x^2) = 0

x^2 = \frac{\pi}{2} + n\pi where n = 0, 1, 2, 3

x = \sqrt{\pi(n+1/2)}

Since we are restricting x between 0 and 3 we can stop at n =  2

So our critical points are at

x = 1.25, y = f(1.25) = 4sin(1.25^2) = 4

x = 2.17 , y = f(2.17) = 4sin(2.17^2) = -4

x = 2.8, y = f(2.8) = 4sin(2.8^2) = 4

For the inflection point, we can take the 2nd derivative and set it to 0

f^[''}(x) = 8(cos(x^2) - xsin(x^2)2x) = 8cos(x^2) - 16x^2sin(x^2) = 0

cos(x^2) = 2x^2sin(x^2)

tan(x^2) = \frac{1}{2x^2}

We can solve this numerically to get the inflection points are at

x = 0.81, y = f(0.81) = 4sin(0.81^2) = 2.44

x = 1.81, y = f(1.81) = 4sin(1.81^2) = -0.54

x = 2.52, y = f(2.52) = 4sin(2.52^2) = 0.27

3 0
3 years ago
Explain in a minimum of 2 sentences how to graph the equation of the absolute value function given a vertex of (-1,3) and a valu
liraira [26]
First, we put a point at the vertex. Then, we extend a line upwards of slope 1/2 to the right of the vertex. Then extend a line upwards of slope -1/2 to the left of the vertex. This will give the graph of the equation.
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3 years ago
Help fast! What is the area ? To thiiiissss
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28(7) + 30(25) = 946 square inches

hope this helps!!
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2 years ago
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