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OleMash [197]
3 years ago
7

A ∠A and ∠ B ∠B are complementary angles. If m ∠ A = ( 2 x − 23 ) ∘ ∠A=(2x−23) ∘ and m ∠ B = ( x + 20 ) ∘ ∠B=(x+20) ∘ , then fin

d the measure of ∠ A ∠A.
Mathematics
1 answer:
son4ous [18]3 years ago
7 0

Answer:

∠A = 99°

Step-by-step explanation:

Complementary angles sum to 180°, thus

∠A + ∠B = 180 ← substitute values

2x - 23 + x + 20 = 180

3x - 3 = 180 ( add 3 to both sides )

3x = 183 ( divide both sides by 3 )

x = 61

Hence

∠A = 2x - 23 = (2 × 61) - 23 = 122 - 23 = 99°

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3 years ago
Which side lengths form a right triangle 30 POINTS!! I DONT HAVE MUCH TIME
Virty [35]

Answer:

To solve this problem, we can use Pythagorean theorem, it tells us that the square of the hypotenuse is equal to the sum of the square of the other two sides.

When we look at these side lengths, we can see that only the second answer is suitable because from the lengths, we can predict that 13 is the length of the hypotenuse, 5 is the length of the shorter leg and 12 is the length of the other leg, and when you actually calculate it, the result is correct as well:

5² + 12² = 25 + 144 = 169

13² = 169

So the answer is B

4 0
3 years ago
Read 2 more answers
Simplify the expression and rationalize the denominator.<br> 36a8b4<br> 7c
il63 [147K]
6a^4b^2(square root)7c
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8 0
1 year ago
The hypotenuse of a right triangle is 6 cm and one side is 2 cm longer than the other side. Find the length of each side to one
MA_775_DIABLO [31]

Answer:

The two legs of the right triangle are approximately 3.1 cm and 5.1 cm and the hypotenuse is 6 cm.

Step-by-step explanation:

Let <em>x</em> be one leg of the right triangle.

Since the other leg is two centimeters longer, it can be represented by the expression:

x + 2 \text{ cm}

According to the Pythagorean Theorem, for a right triangle:

a^2 + b^2 = c^2

Where <em>c</em> is the hypotenuse and <em>a</em> and <em>b</em> are the two legs.

The hypotenuse is given to be 6 cm and the two legs are <em>x</em> and (<em>x</em> + 2). Hence:

(x)^2 + (x+2)^2 = 6^2

Solve for <em>x</em>. Simplify:

x^2 + (x^2 + 4x + 4) = 36

Simplify:

2x^2 + 4x + 4 = 36

Subtract:

2x^2 + 4x - 32 =0

Divide:

x^2 + 2x - 16 = 0

The equation is not factorable, so we can consider using the quadratic formula:

\displaystyle x = \frac{-b\pm\sqrt{b^2 -4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = 2, and <em>c</em> = -16. Substitute:

\displaystyle x= \frac{-(2)\pm\sqrt{(2)^2-4(1)(-16)}}{2(1)}

And evaluate:

\displaystyle \begin{aligned}x &= \frac{-2\pm\sqrt{68}}{2} \\ \\ &= \frac{-2\pm\sqrt{4\cdot 17}}{2} \\ \\ &= \frac{-2\pm2\sqrt{17}}{2} \\ \\ &= -1 \pm \sqrt{17} \end{aligned}

Hence, our two solutions are:

\displaystyle x = -1 + \sqrt{17} \approx 3.1\text{ or } x = -1 - \sqrt{17} \approx -5.1

Lengths cannot be negative, so we can ignore the second solution.

Hence, the value of <em>x</em> or the first side length is about 3.1 centimeters.

Since the other side length is two centimeters longer, the other side is about 5.1 centimeters.

In conclusion, the two legs of the right triangle are approximately 3.1 cm and 5.1 cm and the hypotenuse is 6 cm.

4 0
3 years ago
Distribute: 2 (x + 1)*
fiasKO [112]

Answer:

2x+2

Step-by-step explanation:

You multiple 2 by x and 1 which gives you 2x+2

3 0
3 years ago
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