All categories

3 years ago

Find the sum. 19+(-19)

Mathematics

1 answer:

MrRa [10]3 years ago

6 0

19+(-19)=0

Step-by-step explanation:

So first lets simplify this. We can use the method keep,change, change to do this. Keep the value of positive 19. Then change the + sign to - and the - sign to plus which gets us

19-(+19).

We can remove the +since we know its positive leaving 19-19 which is 0

You might be interested in

Which algebraic expression has a term with a coefficient of 3? A -5y-7 B 3y+1 c 3(y-6) D-2y+5+3

kiruha [24]

B. 3y+1

Hope this helps! :)

7 0

3 years ago

How many 3-digit numbers can you write using only digits 1 and 7? (Of course, digits can repeat.) How many 3-digit numbers can y

Lana71 [14]

Answer:

111,117,177,777,771,711,717,171

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Find the perimeter and area, to the nearest

vredina [299]

Perimeter is equal to 90 in.

Area is approximately equal to 389.71 in.

3 0

3 years ago

Covert each into algebraic equations

marshall27 [118]

Answer:

1) 2x=4x-8

2) 4(x+2)=20

3) 2x-9=4(x+5)

3 0

2 years ago

Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5

zaharov [31]

Answer:

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

$\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}$ or $\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}$

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

$\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}$

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as $\displaystyle \large{a_{n-1} \cdot r = a_n}$ meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as: