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Ber [7]
3 years ago
15

Some students reported how many pets they had. The dot plot shows the data collected: A dot plot is titled Students Pets and lab

eled Number of Pets. The values on the horizontal line are 0, 1, 2, 3, and 4. There are 5 dots above 0, 4 dots above 1, 3 dots above 2, 2 dot above 3, and 1 dot above 4. What do the dots above the number 3 indicate? There are exactly 2 students with 3 pets. There are exactly 3 students with 2 pets. There are exactly 2 students with more than 3 pets. There are exactly 3 students with more than 2 pets.
Mathematics
1 answer:
Kitty [74]3 years ago
8 0

Answer:

A dot plot is similar to histogram wherein they show the frequency of data. In this kind of plot, instead of bars, dots are stacked on their corresponding bin. The bins here are the number of pets, while the dots are the students. So, the 2 dots above number 3 signifies that, there are two students with three pets. The answer is A.

Step-by-step explanation:

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[?] = 108

Step-by-step explanation:

270^\circ  is  3/4 of a whole revolution:  \frac{270^\circ}{360^\circ}=\frac{3}{4} so the area of the sector is 3/4 of the area of the entire circle.

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Solve step by step solution then only i can do it plxx ​
Anuta_ua [19.1K]

Answer:

<h3><u>Let's</u><u> </u><u>understand the concept</u><u>:</u><u>-</u></h3>

Here angle B is 90°

So \triangle ABC and \triangle ABD Are right angled triangle

So we use Pythagoras thereon for solution

<h3><u>Required Answer</u><u>:</u><u>-</u></h3>
  • First in triangle ABC

perpendicular=p=8cm

Hypontenuse =h =10cm

  • We need to find base=b

According to Pythagoras thereon

{\boxed{\sf b^2=h^2-p^2}}

  • Substitutethe values

\longrightarrow\sf b^2=10^2-p^2

\longrightarrow\sf b={\sqrt {10^2-8^2}}

\longrightarrow\sf b={\sqrt{100-64}}

\longrightarrow\bf b={\sqrt {36}}

\longrightarrow\sf b=6

\therefore\overline{BC}=6cm

  • BD=BC+CD

\longrightarrowBD=9+6

\longrightarrowBD=15cm

  • Now in \triangle ABD

Perpendicular=p=8cm

Base =b=15cm

  • We need to find Hypontenuse =AD(x)

According to Pythagoras thereon

{\boxed {\sf h^2=p^2+b^2}}

  • Substitute the values

\longrightarrow\sf h^2=8^2+15^2

\longrightarrow\sf h={\sqrt {8^2+15^2}}

\longrightarrow\sf h={\sqrt {64+225}}

\longrightarrow\sf h={\sqrt {289}}

\longrightarrow\sf h=17cm

\therefore{\underline{\boxed{\bf x=17cm}}}

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Step-by-step explanation:

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