Let x = software program
Let y = video game
x < 200 ; y < 300
x + y < 425
50x ; 35y
x = 200 ; y = 225
50(200) + 35(225) = 10,000 + 7,875 = 17,875
x = 125 ; y = 300
50(125) + 35(300) = 6,250 + 10,500 = 16,750
x = 175 ; y = 250
50(175) + 35(250) = 8,750 + 8,750 = 17,500
It is more profitable to maximize production of software program when working within the limits provided.
The rate for the first is 1 job / 35 minutes and for the second is 1 job / 15 minutes. So combined we get
r = 1/35 + 1/15
3×5×7r = 3 + 7 = 10
r = 10/(105) jobs per minute
We're interested in 1/r
1/r = 105/10 = 10.5 minutes per job
Answer: 10.5 minutes
Answer: 10n^2+n+9
Answer:

Step-by-step explanation:

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Step-by-step explanation:
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