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andrey2020 [161]
3 years ago
9

I need help I am confused

Mathematics
2 answers:
Elodia [21]3 years ago
8 0
633.15 is the answer
nlexa [21]3 years ago
5 0

Answer:

70 Chaperones

Step-by-step explanation:

310            

305

+225           ---------->  840 / 12 = 70

-------------                    

840

Hope this helps!

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The answer you are looking for is 35
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Henry and 28 classmates are going to the roller skating rink. each van can hold 11 students . If all of the van are full except
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you divide 29:11= 2 7/11  

so you have 2 full vans and one with 7 students.

so yes the answer is 7

5 0
3 years ago
Read 2 more answers
Evaluate: Four To The Third Power write the numerical answer only
Alja [10]
The answer is 4^3 and I believe that this is right
7 0
3 years ago
A particle moving in a planar force field has a position vector x that satisfies x'=Ax. The 2×2 matrix A has eigenvalues 4 and 2
andrey2020 [161]

Answer:

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

Step-by-step explanation:

Consider the provided matrix.

v_1=\begin{bmatrix}-3\\1 \end{bmatrix}

v_2=\begin{bmatrix}-1\\1 \end{bmatrix}

\lambda_1=4, \lambda_2=2

The general solution of the equation x'=Ax

x(t)=c_1v_1e^{\lambda_1t}+c_2v_2e^{\lambda_2t}

Substitute the respective values we get:

x(t)=c_1\begin{bmatrix}-3\\1 \end{bmatrix}e^{4t}+c_2\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-3c_1e^{4t}-c_2e^{2t}\\c_1e^{4t}+c_2e^{2t} \end{bmatrix}

Substitute initial condition x(0)=\begin{bmatrix}-6\\1 \end{bmatrix}

\begin{bmatrix}-3c_1-c_2\\c_1+c_2 \end{bmatrix}=\begin{bmatrix}-6\\1 \end{bmatrix}

Reduce matrix to reduced row echelon form.

\begin{bmatrix} 1& 0 & \frac{5}{2}\\ 0& 1 & \frac{-3}{2}\end{bmatrix}

Therefore, c_1=2.5,c_2=1.5

Thus, the general solution of the equation x'=Ax

x(t)=2.5\begin{bmatrix}-3\\1\end{bmatrix}e^{4t}-1.5\begin{bmatrix}-1\\1 \end{bmatrix}e^{2t}

x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

The required position of the particle at time t is: x(t)=\begin{bmatrix}-7.5e^{4t}+1.5e^{2t}\\2.5e^{4t}-1.5e^{2t}\end{bmatrix}

6 0
3 years ago
The perimeter of AABC is 13 cm. It was dilated to
Marina86 [1]

Answer:

you answer will be D. 52 cm.

Step-by-step explanation:

Hope it helps

7 0
2 years ago
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