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g100num [7]
3 years ago
10

How do quadratic functions compare to linear and exponential functions?

Mathematics
1 answer:
pashok25 [27]3 years ago
3 0
Linear functions have a constant rate of change, or velocity more precisely.

Quadratic functions have a constant acceleration, or velocity of velocity.

Exponential functions have no constant rate of change, you can take derivatives all day long and the rate of change will grow or decrease as a factor of the rate...
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Practice multiplying numbers by powers of 10.
Juliette [100K]
Answer:

Multiply (400 + 20 + 3) x 10000

Add 4 zeros to the end of 423

Step-by-step explanation:

423 x 10,000 = Adding the amount of zero’s in 10000 to 423



8 0
3 years ago
A device produces random 64-bit integers at a rate of one billion per second. After how many years of running is it unavoidable
nikitadnepr [17]

Answer:

3171 × 10^(44) years

Step-by-step explanation:

For each bit, since we are looking how many years of running it is unavoidable that the device produces an output for the second time, the possible integers are from 0 to 9. This is 10 possible integers for each bit.

Thus, total number of possible 64 bit integers = 10^(64) integers

Now, we are told that the device produces random integers at a rate of one billion per second (10^(9) billion per second)

Let's calculate how many it can produce in a year.

1 year = 365 × 24 × 60 × 60 seconds = 31,536,000 seconds

Thus, per year it will produce;

(10^(9) billion per second) × 31,536,000 seconds = 3.1536 × 10^(16)

Thus;

Number of years of running is it unavoidable that the device produces an output for the second time is;

(10^(64))/(3.1536 × 10^(16)) = 3171 × 10^(44) years

6 0
3 years ago
Can somebody help me? I need helpp!!!
erma4kov [3.2K]
Independent is the x dependent is the y
independent- time
dependent- total number of knee bends
5 0
3 years ago
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All you need is on the photo
mariarad [96]

Answer:

4^{-3}

Step-by-step explanation:

We\ are\ given\ that,\\4^4*4^{-8}*4\\We\ know\ that,\ for\ any\ real\ number\ n, n^a*n^b=n^{(a+b)}\\Hence,\\First,\ lets\ write\ all\ the\ terms\ in\ an\ exponential\ form.\\4^4*4^{-8}*4^1\\=4^{(4+(-8)+1)}\\=4^{(5-8)}\\=4^{-3}

5 0
3 years ago
I don’t know how to answer this?
dalvyx [7]
Answer: a bigger or equal to 20

Explanation:

2a/5 - 2 _> a/4 + 1

8a/20 - 40/20 _> 5a/20 + 20/20

8a - 40 _> 5a + 20

3a _> 60

a _> 20
3 0
3 years ago
Read 2 more answers
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