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Bogdan [553]
3 years ago
14

Which function is the inverse of f(x)=x^2-25

Mathematics
2 answers:
Georgia [21]3 years ago
8 0

To find the inverse of a function, firt we let

f(x) = y= x^2-25

Now we switch x and y and solve for y .

x = y^2 -25

Adding 25 to both sides

x+25 = y^2

Now we need to get rid of square and for that we take square root on both sides. That is

y = +- \sqrt{x^2 +25}

Therefore, inverse is

f^{-1}(x) = - \sqrt{x^2 +25} , \sqrt{x^2 +25}

Rufina [12.5K]3 years ago
3 0

f(x) = x² -25

Step 1:

write f(x) as y

y=x² -25

Step 2:

switch x as y and y as x

x=y²-25

Step 3:

solve for y

x=y²-25

add 25 to the left side

x+25 = y²

taking square root on both sides

y=√(x+25)

f⁻⁻¹(x) =√(x+25)

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1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x
qaws [65]

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###

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m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ

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Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}

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