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Olegator [25]
3 years ago
8

A bakery sold 145 chocolate cupcakes in a day, which was 29% of the total number of cupcakes sold that day. How many total cupca

kes did the bakery sell that day?
Mathematics
2 answers:
saul85 [17]3 years ago
7 0

Answer:

Step-by-step explanation:

500 cupcakes

Step-by-step explanation:

Given that the 145 cupcakes is 29% of the total number of cupcakes sold that day,

29% --- 145 cupcakes

The total number of cupcakes sold would be 100%.

1% --- 145 ÷29= 5 cupcakes

100% --- 100(5)= 500 cupcakes

Thus, the bakery sold 500 cupcakes that day.

Pavel [41]3 years ago
5 0

Answer:

500 cupcakes

Step-by-step explanation:

Given that the 145 cupcakes is 29% of the total number of cupcakes sold that day,

29% --- 145 cupcakes

The total number of cupcakes sold would be 100%.

1% --- 145 ÷29= 5 cupcakes

100% --- 100(5)= 500 cupcakes

Thus, the bakery sold 500 cupcakes that day.

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B. Systematic

Step-by-step explanation:

<em>Since Quality Control Manager is selecting every 10th soup. This type of Sampling Method is called Systematic Sampling.</em>

Further,

If the whole population is divided into many groups(strata) such that between the group units are heterogeneous and within the group units are homogeneous then units are randomly selected from these groups. This type of sampling is called Stratified Sampling.

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5 0
3 years ago
In the right triangle ?ABC, leg AC=6 cm and leg BC=8 cm. Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5. Find area of ?MN
Licemer1 [7]

Given : In Right triangle ABC, AC=6 cm, BC=8 cm.Point M and N belong to AB so that AM:MN:NB=1:2.5:1.5.

To find : Area (ΔMNC)

Solution: In Δ ABC, right angled at C,

AC= 6 cm, BC= 8 cm

Using pythagoras theorem

AB² =AC²+ BC²

      =6²+8²

     = 36 + 64

→AB²  =100

→AB²  =10²

 →AB  =10

Also, AM:MN:NB=1:2.5:1.5

Then AM, MN, NB are k, 2.5 k, 1.5 k.

→2.5 k + k+1.5 k= 10

→ 5 k =10

Dividing both sides by 2, we get

→ k =2

MN=2.5×2=5 cm, NB=1.5×2=3 cm, AM=2 cm

As Δ ACB and ΔMNC are similar by SAS.

So when triangles are similar , their sides are proportional and ratio of their areas is equal to square of their corresponding sides.

\frac{Ar(ACB)}{Ar(MNC)}=[\frac{10}{5}]^{2}

\frac{Ar(ACB)}{Ar(MNC)}=4

But Area (ΔACB)=1/2×6×8= 24 cm²[ACB is a right angled triangle]

\frac{24}{Ar(MNC)}=4

→ Area(ΔMNC)=24÷4

→Area(ΔMNC)=6 cm²

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