ARIHANNAL

Can anybody help me pleasee I don't understandd

o-na [289]

Hello there.

6(8 - 2y) = 4y

To solve for this, we need to apply the Distributive Property to the left side of the equation. This property allows us to multiply the number outside of the parenthesis by all numbers inside of the parenthesis.

6(8 - 2y)
6(8) + 6(-2y)
48 - 12y

Now, let’s take a look at our equation.

-12y + 48 = 4y

To make things more simple, we’ll add 12y to both sides of the equation. This will cancel out -12y on the left side of the equation and will turn 4y on the right side of the equation into 16y.

Our new equation is:

16y = 48

Now all we need to do is divide both sides by 16 to solve for y.

16y / 16 = y
48 / 16 = 3

Our final answer and solution is:

Y = 3

I hope this helps!

4 0

3 years ago

Help me please

Fittoniya [83]

110a3b3c4 is yours answer.

8 0

2 years ago

You want to get from a point A on the straight shore of the beach to a buoy which is 54 meters out in the water from a point B o

anyanavicka [17]

Answer:

$x =\dfrac{45 \sqrt{6}}{ 2}$

Step-by-step explanation:

From the given information:

The diagrammatic interpretation of what the question is all about can be seen in the diagram attached below.

Now, let V(x) be the time needed for the runner to reach the buoy;

∴ We can say that,

$\mathtt{V(x) = \dfrac{70-x}{7}+\dfrac{\sqrt{54^2+x^2}}{5}}$

In order to estimate the point along the shore, x meters from B, the runner should stop running and start swimming if he want to reach the buoy in the least time possible, then we need to differentiate the function of V(x) and relate it to zero.

i.e

The differential of V(x) = V'(x) =0

= $\dfrac{d}{dx}\begin {bmatrix} \dfrac{70-x}{7} + \dfrac{\sqrt{54^2+x^2}}{5} \end {bmatrix}= 0$

$-\dfrac{1}{7}+ \dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}=0$

$\dfrac{1}{5}\times \dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{5x}{\sqrt{54^2+x^2}}= \dfrac{1}{7}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{1}{\dfrac{7}{5}}$

$\dfrac{x}{\sqrt{54^2+x^2}}= \dfrac{5}{7}$

squaring both sides; we get

$\dfrac{x^2}{54^2+x^2}= \dfrac{5^2}{7^2}$

$\dfrac{x^2}{54^2+x^2}= \dfrac{25}{49}$

By cross multiplying; we get

$49x^2 = 25(54^2+x^2)$

$49x^2 = 25 \times 54^2+ 25x^2$

$49x^2-25x^2 = 25 \times 54^2$

$24x^2 = 25 \times 54^2$

$x^2 = \dfrac{25 \times 54^2}{24}$

$x =\sqrt{ \dfrac{25 \times 54^2}{24}}$

$x =\dfrac{5 \times 54}{\sqrt{24}}$

$x =\dfrac{270}{\sqrt{4 \times 6}}$

$x =\dfrac{45 \times 6}{ 2 \sqrt{ 6}}$

$x =\dfrac{45 \sqrt{6}}{ 2}$

8 0

3 years ago

Simplify and Evaluate

zalisa [80]

$\dfrac{2^{-1} + 5^{-1}}{10^{-1} - 5^{-2}} =$

$= \dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{5^2}}$

$=\dfrac{\frac{1}{2} + \frac{1}{5}}{\frac{1}{10} - \frac{1}{25}}$

$=\dfrac{\frac{5}{10} + \frac{2}{10}}{\frac{5}{50} - \frac{2}{50}}$

$=\dfrac{\frac{7}{10}}{\frac{3}{50}}$

$= \frac{7}{10} \times \frac{50}{3}$

$= \frac{7}{1} \times \frac{5}{3}$

$= \frac{35}{3}$

4 0

3 years ago

Solve the equation. Find x.<br> 20x + 5 - 0 = 5x + 32.5*2

SVEN [57.7K]

Answer:

x = 4

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

20x+5−0=5x+(32.5)(2)

20x+5+0=5x+65

(20x)+(5+0)=5x+65(Combine Like Terms)

20x+5=5x+65

Step 2: Subtract 5x from both sides.

20x+5−5x=5x+65−5x

15x+5=65

Step 3: Subtract 5 from both sides.

15x+5−5=65−5

15x=60

Step 4: Divide both sides by 15.

15x

15

=

60

15

x=4

Hope this helps!

:)

(:

:)

(:

7 0

3 years ago

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