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Lubov Fominskaja [6]
3 years ago
6

Plz help me please please

Mathematics
1 answer:
siniylev [52]3 years ago
8 0

Answer:

ok so it is 22 c 3 for this answer

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What additional information is needed to prove that
erik [133]
The answer is <a is congruent to < d

because you already have <abe = <dbe 
5 0
3 years ago
Show that each of these conditional statements is a tautology by using truth tables. a) [¬p ∧ (p ∨ q)] → q b) [(p → q) ∧ (q → r)
nlexa [21]

Step-by-step explanation:

To show that a statement is a tautology using truth table - is to show that all the entries in the expression are truths T.

We can do this by taking each statement, expression by expression. For example, to show that

[~p ∧ (p ∨ q)] → q

is a tautology, knowing we have 3 columns, we have 2^3 = 8 rows. We start by putting putting truth values for p, q, and r respectively

Next, we find ~p, then find (p ∨ q), then find ~p ∧ (p ∨ q), before finally arriving at the required [~p ∧ (p ∨ q)] → q

TERMINOLOGIES AND SYMBOLS

- T means Truth

- F means False

- ~p means negation of p.

~p is F if p is T, and vice versa

- ∧ means conjunction.

p ∧ q is T only if p is T and q is T.

- ∨ means disjunction.

p ∨ q is T if either p or q is T.

- → is for conditional 'if then'

p → q is T if both p and q are T, or both p and q are F, or p is F and q is T, otherwise, it is F.

THE STEP BY STEP WORKINGS FOR THE STATEMENTS GIVEN ARE IN THE ATTACHMENT.

8 0
3 years ago
Read 2 more answers
Find the area of the shaded region. round your answer to the nearest hundredth
Alex Ar [27]

Answer:

16 meters

Step-by-step explanation:

sana makatulong

5 0
3 years ago
11 + 11 = 4 22 + 22 = 16 33 + 33 = ?
Anon25 [30]

Answer:

66

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Help me please i cant get it
Leni [432]

Answer:

Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.

The total cost of both games is:

X + Y

We know that both games cost just above AED 80

Then:

X + Y > AED 80

From this, we want to prove that at least one of the games costed more than AED 40.

Now let's play with the possible prices of X, there are two possible cases:

X is larger than AED 40

X is equal to or smaller than AED 40.

If X is more than AED 40, then we have a game that costed more than AED 40.

If X is less than or equal to AED 40, then:

X ≥ AED 40

Now let's take the maximum value of X in this scenario, this is:

X = AED 40

Replacing this in the first inequality, we get:

X + Y > AED 80

Replacing the value of X we get:

AED 40 + Y  > AED 80

Y > AED 80 - AED 40

Y > AED 40

So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.

So we proven that in all the possible cases, at least one of the two games costs more than AED 40.

7 0
3 years ago
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