All categories

3 years ago

Evaluate the inequality 6x-2y+8 when x=3 and y=2 show your work

Mathematics

2 answers:

tatuchka [14]3 years ago

7 0

Answer:

Step-by-step explanation:

6x-2y+8

(6 • 3) - (2 • 2) + 8

18 - 4 + 8

(i think)

snow_tiger [21]3 years ago

3 0

Answer:

Step-by-step explanation:

6(3)-2(2)+8

18-4+8

14+8

You might be interested in

Please help me with these!

Dvinal [7]

Answer:

Step-by-step explanation:

A1. C = 104°, b = 16, c = 25

Law of Sines: B = arcsin[b·sinC/c} ≅ 38.4°

A = 180-C-B = 37.6°

Law of Sines: a = c·sinA/sinC ≅ 15.7

A2. B = 56°, b = 17, c = 14

Law of Sines: C = arcsin[c·sinB/b] ≅43.1°

A = 180-B-C = 80.9°

Law of Sines: a = b·sinA/sinB ≅ 20.2

B1. B = 116°, a = 11, c = 15

Law of Cosines: b = √(a² + c² - 2ac·cosB) = 22.2

A = arccos{(b²+c²-a²)/(2bc) ≅26.5°

C = 180-A-B = 37.5°

B2. a=18, b=29, c=30

Law of Cosines: A = arccos{(b²+c²-a²)/(2bc) ≅ 35.5°

Law of Cosines: B = arccos[(a²+c²-b²)/(2ac) = 69.2°

C = 180-A-B = 75.3°

6 0

3 years ago

A large tank is filled to capacity with 300 gallons of pure water. brine containing 5 pounds of salt per gallon is pumped into t

Licemer1 [7]

If $A(t)$ is the amount of salt in the tank at time $t$ , then the rate at which this amount changes over time is given by the ODE

$A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{5\text{ lb}}{1\text{ gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}$

$A'(t)+\dfrac1{100}A(t)=15$

We're told that the tank initially starts with no salt in the water, so $A(0)=0$ .

Multiply both sides by an integrating factor, $e^{t/100}$ :

$e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=15e^{t/100}$
$\left(e^{t/100}A(t)\right)'=15e^{t/100}$
$e^{t/100}A(t)=1500e^{t/100}+C$
$A(t)=1500+Ce^{-t/100}$

Since $A(0)=0$ , we have

$0=1500+C\implies C=-1500$

so that the amount of salt in the tank over time is given by

$A(t)=1500(1-e^{-t/100})$

After 10 minutes, the amount of salt in the tank is

$A(10)=1500(1-e^{-1/10})\approx142.74\text{ lb}$

8 0

4 years ago

The reyes family but for concert tickets for $252 what was the price per ticket

Bas_tet [7]

If you mean "The Reyes Family bought for concert tickets for $252",

Consider the total price is $252 and that there are four tickets. You are looking for the price of one ticket so view it as

Total Price = $252
Total Tickets = 4

Total Price divided by Total Tickets =
$\frac{252}{4}$
Then divide both sides by four because 4 divided by 4 is 1 ticket.
$\frac{252 \div 4}{4 \div 4} = \frac{63}{1}$

Then you should get 63 divided by 1.
63 divided by 1 is 63, So your answer is

"The price of one ticket that the Reyes Family bought is 63 dollars."

7 0

3 years ago

Janice bought juice packets for the 15 players on the soccer team. The juice packets come in boxes of 6. How many boxes did jani

lara [203]

Janice bought 3 boxes.

Each box has 6 juice pockets. However, there are 15 players on the soccer team. Two boxes would not be enough, since that would only total 12 juice packets.

So, Janice has to buy 3 boxes, which is 18 juice packets.

8 0

3 years ago

What division problem can be represented using the number line?

inna [77]

A. (10/3) / (5/3)
I got it right :)

3 0

3 years ago