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3 years ago

Evaluate the inequality 6x-2y+8 when x=3 and y=2 show your work

Mathematics

2 answers:

tatuchka [14]3 years ago

7 0

Answer:

Step-by-step explanation:

6x-2y+8

(6 • 3) - (2 • 2) + 8

18 - 4 + 8

(i think)

snow_tiger [21]3 years ago

3 0

Answer:

Step-by-step explanation:

6(3)-2(2)+8

18-4+8

14+8

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A playground is in the shape of a square with each side equal to 109 yards. It has skating rinks in the shape of the quadrants o

I am Lyosha [343]

Answer:

radius = 30 yd , cost of cement = $7065

Step-by-step explanation:

First we will find the area of the circular sectors. From that we can find the cost of cement and their radius.

The area of the playground is ...

playground area = (109 yd)^2 = 11,881 yd^2

Then the area of the skating rinks is:

rink area = playground area - remaining field

rink area = 11,881 yd^2 - 9,055 yd^2 = 2,826 yd^2

Then the cost of cement for the rink area is ...

(2826 yd^2)($2.50 yd^2) = $7065

The four quarter-circle skating rinks add to a total area of a full circle. That area is given by ...

A = πr^2

Put the values in the formula:

2826 = 3.14r^2

Divide both sides by 3.14

900 = r^2

By taking square root at both sides we get,

30 = r

The radius of each quadrant is 30 yards....

6 0

2 years ago

What is an equation of the line that passes through the points (−2,−3) and (−1,2)?

mariarad [96]

Just graph is bruv. The app is called desmos

4 0

3 years ago

Hi everyone! I have a very urgent work so please help me as fast as you could! I beg you. Your immediate action would be kindly

romanna [79]

Answer:

-3/8

Step-by-step explanation:

PemDas

2/3 x 3/4= 1/2

3/4 x -1/2 = -3/8

full equation is now

1/2 - 1/2 + -3/8

1/2-1/2 =0

-3/8 remains

3 0

2 years ago

If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by

Vitek1552 [10]

Answer:

a) Average velocity at 0.1 s is 696 ft/s.

b) Average velocity at 0.01 s is 7536 ft/s.

c) Average velocity at 0.001 s is 75936 ft/s.

Step-by-step explanation:

Given : If a ball is thrown straight up into the air with an initial velocity of 70 ft/s, its height in feet after t seconds is given by $y = 70t-16t^2$ .

To find : The average velocity for the time period beginning when t = 2 and lasting. a. 0.1 s. , b. 0.01 s. , c. 0.001 s.

Solution :

a) The average velocity for the time period beginning when t = 2 and lasting 0.1 s.

$(\text{Average velocity})_{0.1\ s}=\frac{\text{Change in height}}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{h_{2.1}-h_2}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{(70(2.1)-16(2.1)^2)-(70(0.1)-16(0.1)^2)}{0.1}$

$(\text{Average velocity})_{0.1\ s}=\frac{69.6}{0.1}$

$(\text{Average velocity})_{0.1\ s}=696\ ft/s$

b) The average velocity for the time period beginning when t = 2 and lasting 0.01 s.

$(\text{Average velocity})_{0.01\ s}=\frac{\text{Change in height}}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{h_{2.01}-h_2}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{(70(2.01)-16(2.01)^2)-(70(0.01)-16(0.01)^2)}{0.01}$

$(\text{Average velocity})_{0.01\ s}=\frac{75.36}{0.01}$

$(\text{Average velocity})_{0.01\ s}=7536\ ft/s$

c) The average velocity for the time period beginning when t = 2 and lasting 0.001 s.

$(\text{Average velocity})_{0.001\ s}=\frac{\text{Change in height}}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{h_{2.001}-h_2}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{(70(2.001)-16(2.001)^2)-(70(0.001)-16(0.001)^2)}{0.001}$

$(\text{Average velocity})_{0.001\ s}=\frac{75.936}{0.001}$

$(\text{Average velocity})_{0.001\ s}=75936\ ft/s$

5 0

3 years ago

F (x) = – 3x² + 3x + 7<br>Find f(8)

aliya0001 [1]

Answer:

-161

Step-by-step explanation:

$f(x)=-3x^2+3x+7\\f(8)=-3(8)^2+3(8)+7\\f(8)=-3(64)+24+7\\f(8)=-192+31\\=-161$

7 0

3 years ago