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Setler79 [48]
3 years ago
13

Which of the following expressions represents a function?

Mathematics
1 answer:
Mrac [35]3 years ago
7 0

Answer: the first option, {(1, 2), (4, –2), (8, 3), (9, –3)}

Explanation:

1) A function is a rule (relation) that permits relate an input unambiguously to an output.

In {(1, 2), (4, –2), (8, 3), (9, –3)}, clearly this the relation:

pari input output

(1, 2) 1 2

(4, –2) 4 -2

(8, 3) 8 3

(9, –3) 9 -3

2) y² = 16 − x² is not a function, because you cannot pair unambiguously some y values with some x values.

For example: the value x = 2 is related with both y = √12 and - √12, which you can prove:

x = 2 ⇒ y² = 16 - (2)² = 16 - 4 = 12 ⇒ y = +/- √12

3) You can prove 2x² + y² = 5 is not a function is the same way:

2x² + y² = 5 ⇒ y² = 5 - 2x², so for most x-values in the domain there are two different possible values of y.

3) x = 7

The input can only be 7 and the output can be any number, so does not relate 7 with any particular number: it can be -2000, 0, √5, .... any number.

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Answer:

The answer is False maybe

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Need ASAP plz help!! These are the numbers you use. <br>15 27 28 31 34 42 52
Dahasolnce [82]

im sorry but did you ever get the answer?


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Simplify the expression.<br><br> 10 + 3(2v - 3)
Vikentia [17]

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6v+1

Step-by-step explanation:

7 0
3 years ago
In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo
Scorpion4ik [409]

Answer:

x=\frac{8}{3}\ cm

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

A=\frac{1}{2}(AB)(BC)

we have

A=17\ cm^2

AB=(3x-2)\ cm

BC=(x+3)\ cm

substitute the values

17=\frac{1}{2}(3x-2)(x+3)

34=(3x-2)(x+3)

34=3x^2+9x-2x-6

3x^2+7x-6-34=0

3x^2+7x-40=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

3x^2+7x-40=0

so

a=3\\b=7\\c=-40

substitute in the formula

x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}

x=\frac{-7(+/-)\sqrt{529}} {6}

x=\frac{-7(+/-)23} {6}

x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}

x=\frac{-7(-)23} {6}=-5

therefore

The solution is

x=\frac{8}{3}\ cm

6 0
3 years ago
.........................
Zigmanuir [339]

Answer:

A

Step-by-step explanation:

given 3xy + 4yz + 8xz = 10

subtract 8xz from both sides leaving the terms in y together

3xy + 4yz = 10 - 8xz

take out the common factor y on the left side

y(3x + 4z) = 10 - 8xz

divide both sides by (3x + 4z)

y = \frac{10-8xz}{3x+4z} → A


5 0
3 years ago
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