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Dimas [21]
3 years ago
9

This set has me absolutely confused. Can anyone help with the first problem?

Mathematics
1 answer:
erma4kov [3.2K]3 years ago
8 0

Answer:

The other endpoint is ( -1,15)

Step-by-step explanation:

21.

 The x coordinate of the midpoint is the  sum of the x coordinate of the endpoints  divided by 2

(-5 +x)/2 = -3

Multiply each side by 2

-5+x = -6

Add 5 to each side

-5+x+5 = -6+5

x = -1

The y coordinate of the midpoint is the  sum of the y coordinate of the endpoints  divided by 2

(-1 +y)/2 = -8

Multiply each side by 2

-1+y = -16

Add 1 to each side

-1+y+1 = -16+1

y = -15

The other endpoint is ( -1,15)

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mr_godi [17]

Answer:

Step-by-step explanation:

ab=ab (common)

angle d = angle c (isosceles prperty)

angle a = angle a (common)

there for the triangle is congruent so sides are congruent by CPCT

5 0
4 years ago
Có hai hộp sản phẩm. Trong đó, hộp I có: 6 sản phẩm A, 4 sản phẩm B và 6 sản phẩm C, hộp II có: 5 sản phẩm A, 3 sản phẩm B và 8
storchak [24]

Hello

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7 0
3 years ago
Almost all medical schools require applicants to take the Medical College Admission Test (MCAT). To estimate the mean score of t
jenyasd209 [6]

Answer:

97.92% probability that the mean score of your sample is between 22 and 28

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 25, \sigma = 6.5, n = 25, s = \frac{6.5}{\sqrt{25}} = 1.3

What is the probability that the mean score of your sample is between 22 and 28

This is the pvalue of Z when X = 28 subtracted by the pvalue of Z when X = 22. So

X = 28

Z = \frac{X - \mu}{\sigma}

By the Central Limit theorem

Z = \frac{X - \mu}{s}

Z = \frac{28 - 25}{1.3}

Z = 2.31

Z = 2.31 has a pvalue of 0.9896

X = 22

Z = \frac{X - \mu}{s}

Z = \frac{22 - 25}{1.3}

Z = -2.31

Z = -2.31 has a pvalue of 0.0104

0.9896 - 0.0104 = 0.9792

97.92% probability that the mean score of your sample is between 22 and 28

8 0
3 years ago
K+2 is greater than 12 and k+2 is less than or equal to 18
krok68 [10]

k + 2 > 12

so k > 10

k + 2 ≤ 18

so k ≤ 16

Solution is    10 < k ≤ 16  

4 0
4 years ago
The price of a cellular telephone plan is based on peak and nonpeak service. Kelsey used 45 peak minutes and 50 nonpeak minutes
Oxana [17]
We can build a system of two linear equations with two unknowns with the info provided in the problem, one with Kelsey info and one with Mitch info like so:
Lets call p the amount on peak minutes and n the amount of non-peak minutes:
45p + 50n = 27.75
70p + 30n = 36
lets reduce the equations dividing the first by 5:
9p + 10n = 5.55
<span>70p + 30n = 36
</span>now, to eliminate n, lets multiply the first equation by -3 and add the two equations:
-27p - 30n = -16.65
<span>70p + 30n = 36
</span>----------------------------
43p + 0 = 19.35
p = 19.35<span>/43
p = 0.45
therefore the peak rate is $0.45 per minute
lets substitute in one of the original equations this result:
</span><span>45p + 50n = 27.75
</span>45(0.45) + 50n = 27.75
20.25 <span>+ 50n = 27.75
50n = 27.75 - 20.25
50n = 7.5
n = 7.5/50
n = 0.15
therefore the non-peak rate per minute is $0.15</span>
5 0
3 years ago
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