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4 years ago

Help Please I Need Help

Mathematics

1 answer:

Ket [755]4 years ago

5 0

Answer:

Linear: "You start with $3 and save $1 each month."

Quadratic: "Your total savings is 3 times the number of months multiplied by itself."

Exponential: "You save $3 the first month, and then each month the amount triples."

Explanation: I did the work. :)

PLEASE MARK BRAINLIEST!

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You want to buy new kitchen appliances 2 years from now, and you plan to save $8,200 per year, beginning one year from today. yo

bulgar [2K]

Even though the money is required 2 years from now, the first deposit is made only a year from now, therefore in the bank for only one year.
The second deposit will be in the bank the same day it will be taken out, so no interest whatsoever.

Thus future value
= 8200(1.062)+8200
=$16908.40
will be available assuming compounding annually.

4 0

3 years ago

joseph accepted a new job at a company with a contract guaranteeing annual raises. Joseph will get a raise of $5000 every year a

Stels [109]

Answer:S = 70,000 + 5000n

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3 years ago

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Gummi bears come in twelve flavors, and you have one of each flavor. Suppose you split your gummi bears among three people (Adam

aliina [53]

Step-by-step explanation:

From the given gummi bear, the chance that Adam is selected for any draw is 1/3 as well as the chance he is not selected at any draw is 2/3.

a). The probability of Adam getting exactly three gummi bears = P(Adam gets selected at 3 draws and not selected at the remaining 9 draws)

= $(\frac{1}{3})^3 (\frac{2}{3})^9 = \frac{2^9}{3^{12}}$

Now, the 3 draws where Adam gets selected can be any 3 out of 12 draws in ${\overset{12}C}_3$ = 220

Thus, probability of Adam getting three gummi bears = $220 \times \frac{2^9}{3^{12}}$

= 0.21186

b). Probability that Adam will get the three gummi bears given each person will received at the most 1 gummi bear

= P(of the remaining 9 draws after assigning one gummi bear to each one, Adam gets selected at 2 draws and not selected at 7 draws) = ${\overset{9}C}_2 (\frac{1}{3})^2 (\frac{2}{3})^7$

= 0.23411

c). Let X = Number of the gummi bears which Adam will get. Then, X = number of draws out of 12 draws Adam gets selected and X ~ B(12, 1/3). So, Adam will get gummi bears= mean of B(12, 1/3) = 12 x (1/3) = 4

d). Let Y = Number of the gummi bears that Adam will get, given each person will received at the most 1 gummi bear Then, Y = number of draws Adam gets selected in the remaining 9 draws and Y ~ B(9, 1/3). So, the expected number of bears that Adam gets given each person received at least 1 gummi bear

= 1 + mean of B(9, 1/3) = 4

e). When every one gets atleast one gummi bear, the new sample size will be 9 and so we can say that there is a reduction in variance.

8 0

3 years ago

Factor completely 16x^2y^4z^3+33xy^8z^5

34kurt

Answer:

xy^4 z^3 ( 16x + 33y^4 z^2)

Step-by-step explanation:

step 1 : see what variable you can take out , start with x see if there is x in the left and right side. and how many time you can take it out

next y same thing and then last z

with x = left side you x^2 and right side you have x = so u can take x out once left you with x

with y = left side y^4 and right side y^8 so you can take out y ^4 out left you with y^4

with z = left side z^3 and right side z ^5 you can take out z^3 left you with z^2

5 0

3 years ago

There are 24 people at a party and each person eats 1/8 of a cake. There was not any cake leftover. How many cakes were at the p

sasho [114]

Answer: 3 cakes were at the party

Step-by-step explanation:

Multiply 1/8*24 to find the exact number of cakes that were at the party

Hope this helps :)

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3 years ago

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