All categories

2 years ago

Solve for x. {x}{3}+2=-13

1 answer:

8 0

Step 1: Simplify both sides of the equation.
3
x
+
2
=
−
13
Step 2: Subtract 2 from both sides.
3
x
+
2
−
2
=
−
13
−
2
3
x
=
−
15
Step 3: Divide both sides by 3.
3
x
3
=
−
15
3
x
=
−
5

You might be interested in

Please help me with this!

s344n2d4d5 [400]

Answer:

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Need help please it’s due today show work

Diano4ka-milaya [45]

Answer:

Step-by-step explanation:

6 0

2 years ago

Math question <br> -3y+12 = -48

svetoff [14.1K]

Answer:

y = 20

Step-by-step explanation:

-3y+12 = -48 . -12 from both sides

-3y = -60 . ÷3 on both sides

y = 20

7 0

2 years ago

Read 2 more answers

I need help on my quiz!

Fantom [35]

I can’t see good this image

3 0

2 years ago

Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers

Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the $x^2$ coefficient is 1, i.e. the equation is written like $x^2+bx+c=0$ , then you can say the following about the coefficients b and c:

$b$ is the opposite of the sum of the roots
$c$ is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

$4+(-2) = 4-2 = 2 \implies b = -2$
$4 \cdot (-2) = -8 \implies c = -8$

So, the equation is $x^2-2x-8=0$

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

$\dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}$
$\dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}$

And so the equation is

$x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0$

In order to have integer coefficients, you can multiply both sides of the equation by 8:

$8x^2 - 10 + 3 = 0$

5 0

2 years ago