Please, I need help with this! :(

Mathematics

1 answer:

Serggg [28]2 years ago

7 0

Answer:

Step-by-step explanation:

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Solve the following 1-step equation for x

shtirl [24]

X/0.5 = 24
X/0.5(0.5) = 24(0.5)
X = 12

5 0

2 years ago

PLZ HELP PLZ HELP WHATS THE ANSWER

avanturin [10]

For the first equation it should be 1 and 4 because 7(1)+6(4) would simplify to 7+24 which equals 31.

Then for the second equation, well... there’s multiple answers:

First would be 3 and -2 because 3(3)-10(-2) simplifies to 9+20=29.

Another one would be 23 and 4 because 3(23)-10(4) simplifies to 69-40=29.

Hopefully this helps :D

4 0

2 years ago

The distribution of IQ scores can be modeled by a normal distribution with mean 100 and standard deviation 15.

evablogger [386]

Answer:

4.4% of the population with IQ between 120 and 125.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100

Standard Deviation, σ = 15

We are given that the distribution of IQ scores is a bell shaped distribution that is a normal distribution.

a) Let X be a person's IQ score.

Then, density functions for IQ scores is given by:

$P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{z^2}{2}}\\\\\text{where,}\\\\z = \frac{x-\mu}{\sigma}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-\mu)^2}{2\sigma^2}}\\\\P(x) = \displaystyle\frac{1}{2\sqrt{2\pi}}e^{-\frac{(x-100)^2}{450}}$

b) P(population with IQ between 120 and 125.)

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

$P(120 \leq x \leq 125) = P(\displaystyle\frac{120 - 100}{15} \leq z \leq \displaystyle\frac{125-100}{15}) = P(1.33 \leq z \leq 1.66)\\\\= P(z \leq 1.66) - P(z < 1.33)\\= 0.952 - 0.908 = 0.044 = 4.4\%$