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Darya [45]
3 years ago
7

2 multiplied by -1 divided by 2

Mathematics
1 answer:
dusya [7]3 years ago
3 0

Answer:

-1

Step-by-step explanation:

2 * -1 = -2

Then, -2 / 2  = 1

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Tina creates a dot plot using the match scores 3, 2, 4, 5, 2, 3, 1, 2, 1, and 5. Which of the following dot plots represents the
bogdanovich [222]
The answer is

B. A dot plot is shown with the title Match Scores. There are 2 dots over score 1, 3 dots over score 2, 2 dots over score 3, 1 dot over score 4, and 2 dots over score 5.

100% Verified!

Hope This Helps!:)

7 0
3 years ago
Assume that you have a sample of n 1 equals 6​, with the sample mean Upper X overbar 1 equals 50​, and a sample standard deviati
tigry1 [53]

Answer:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

df=6+5-2=9

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

Step-by-step explanation:

Data given

n_1 =6 represent the sample size for group 1

n_2 =5 represent the sample size for group 2

\bar X_1 =50 represent the sample mean for the group 1

\bar X_2 =38 represent the sample mean for the group 2

s_1=7 represent the sample standard deviation for group 1

s_2=8 represent the sample standard deviation for group 2

System of hypothesis

The system of hypothesis on this case are:

Null hypothesis: \mu_1 \leq \mu_2

Alternative hypothesis: \mu_1 > \mu_2

We are assuming that the population variances for each group are the same

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic for this case is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

The pooled variance is:

S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

We can find the pooled variance:

S^2_p =\frac{(6-1)(7)^2 +(5 -1)(8)^2}{6 +5 -2}=55.67

And the pooled deviation is:

S_p=7.46

The statistic is given by:

t=\frac{(50 -38)-(0)}{7.46\sqrt{\frac{1}{6}+\frac{1}{5}}}=2.656

The degrees of freedom are given by:

df=6+5-2=9

The p value is given by:

p_v =P(t_{9}>2.656) =0.0131

Since the p value is higher than the significance level given of 0.01 we don't have enough evidence to conclude that the true mean for group 1 is significantly higher thn the true mean for the group 2.

4 0
3 years ago
40 is 20% of x. If x is 80% of y, then what is the sum of x and y?
Tanzania [10]

40 is 20% of x

40 = .2 * x

40/.2 = x

x =200


x is 80% of y

x = .8 * y

200 = .8 *y

200/.8 = y

250 =y


x+y

200+250

450


5 0
3 years ago
Round .0091 to the nearest hundredths
azamat
0.0091 rounded to the nearest hundredths is 0.01.
I hope this helped!!
3 0
3 years ago
What the common Denominator of 7/8 and 3/10?
ankoles [38]
The common denominator would be 40
3 0
3 years ago
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