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Stella [2.4K]
3 years ago
6

Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to Volume of bucket= ½ ft3 Weight of empty bucket 20.

3 lb Weight of bucket filled with dry rodded coarse aggregate 69.6 Ib determine its unit weight. The following data are obtained: a. Calculate the dry-rodded unit weight If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles.

Engineering
1 answer:
Darina [25.2K]3 years ago
3 0

Answer: a) 98.6lb/ft^3

b) 60%

Explanation: The Dry-Rodded Unit Weight of an aggregate is the weight required to fill a contained or a specified unit volume, after it has been rodded to attain maximum packing.

Please find the attached file for the solution

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How can pavement markings indicate that you are driving in the right direction?
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2 years ago
Compute the fundamental natural frequency of the transverse vibration of a uniform beam of rectanqular cross section, with one e
marshall27 [118]

Answer:

The natural angular frequency of the rod is 53.56 rad/sec

Explanation:

Since the beam is free at one end and fixed at the other hence the beam is a cantilevered beam as shown in the attached figure

We know that when a unit force is placed at the end of a cantilever the displacement of the free end is given by

\Delta x=\frac{PL^3}{3EI}

Hence we can write

P=\frac{3EI\cdot \Delta x}{L^3}

Comparing with the standard spring equation F=kx we find the cantilever analogous to spring with k=\frac{3EI}{L^3}

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'm' is the mass of the load

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\omega _{beam}=\sqrt{\frac{\frac{3EI}{L^{3}}}{Area\times density}}

\omega _{beam}=\sqrt{\frac{\frac{3\times 20.5\times 10^{10}\times \frac{0.1\times 0.3^3}{12}}{5.9^{3}}}{0.3\times 0.1 \times 7830}}=53.56rad/sec

8 0
3 years ago
Read 2 more answers
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