Answer:
for 1st question the answer is 5th option.
for 2nd question the answer is 2nd option
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Answer:

Explanation:
We are given:
m = 1.06Kg

T = 22kj
Therefore we need to find coefficient performance or the cycle


= 5
For the amount of heat absorbed:

= 5 × 22 = 110KJ
For the amount of heat rejected:

= 110 + 22 = 132KJ
[tex[ q_H = \frac{Q_L}{m} [/tex];
= 
= 124.5KJ
Using refrigerant table at hfg = 124.5KJ/Kg we have 69.5°c
Convert 69.5°c to K we have 342.5K
To find the minimum temperature:
;

= 285.4K
Convert to °C we have 12.4°C
From the refrigerant R -134a table at
= 12.4°c we have 442KPa
Answer:
t = 25.10 sec
Explanation:
we know that Avrami equation

here Y is percentage of completion of reaction = 50%
t is duration of reaction = 146 sec
so,


taking natural log on both side
ln(0.5) = -k(306.6)

for 86 % completion




t = 25.10 sec
Answer:
Smoke detectors on the robot.
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Answer:
see explaination
Explanation:
Please kindly check attachment for the step by step solution of the given problem.
The attached files has the solved problem.