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4 years ago

Solve the division problem -1 3/5 diveded by (-2/3 writ the answer as a mixed number

Mathematics

2 answers:

seropon [69]4 years ago

5 0

Answer: 2 2/5

Turn -1 3/5 into an Improper Fraction

Multiply -1×5 and get -5. Now add 3 and get -8.

-1 3/5 = -8/5

Do Keep Change Flip

Keep: -8/5

Change: ÷ into ×

Flip: -2/3 into -3/2

Multiply

-8/5×-3/2=12/5

Simplify

12/5 = 2 2/5

victus00 [196]4 years ago

5 0

Answer:

2 2/5

Step-by-step explanation:

see attached

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Ests show that the first photo detector isacceptable with probability 3/5. When the first photo detector is acceptable, the seco

vredina [299]

Answer:

The probability that exactly one photo detector of a pair is acceptable is $\frac{19}{25}$ .

Step-by-step explanation:

Let the A = first photo detector is acceptable and B = second photo detector is acceptable .

The information provided is:

$P(A) = \frac{3}{5} \\P(B|A)=\frac{4}{5}\\ P(B|A^{c})=\frac{2}{5}$

The law of total probability states that:

$P(X)=P(X|Y)P(Y)+P(X|Y^{c})P(Y^{c})\\$

Using the law of total probability determine the probability of B as follows:

$P(B)=P(B|A)P(A)+P(B|A^{c})P(A^{c})\\=(\frac{4}{5}\times\frac{3}{5} )+(\frac{2}{5}(1- \frac{3}{5}))\\=\frac{12}{25}+\frac{4}{25}\\ =\frac{16}{25}$

The addition rule of probability is:

$P(Y\cup X) = P(Y) + P(X) - P(Y\cap X)\\$

Compute the probability that exactly one photo detector of a pair is acceptable using the addition rule of probability as follows:

$P(A\cup B) = P(A) + P(B) - P(A\cap B)\\=P(A) + P(B) - P(B|A)P(A)\\=\frac{3}{5} +\frac{16}{25} -[\frac{4}{5}\times\frac{3}{5}] \\=\frac{3}{5} +\frac{16}{25}-\frac{12}{25}\\=\frac{15+16-12}{25}\\= \frac{19}{25}$

Thus, the probability that exactly one photo detector of a pair is acceptable is $\frac{19}{25}$ .

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