Answer:
The tip should be $9.00
Step-by-step explanation:
Answer:
9-3x=0
Step-by-step explanation:
Add 3x to both sides
9=3x
divide both sides by 3
3=x
x=3
The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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You will need to convert them into improper fractions, subtract them, and convert them back to mixed numbers.
5 1/8 - 2 4/8
41/8 - 20/8
21/8
2 5/8
Your answer is 2 5/8.
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